Explanation Write the expression for the reduced pressure at state 5. p ′ r 5 = ( p 5 p 4 ) p ′ r 4 (I) Here, the pressure at state 4 is p 4 , the pressure at state 5 is p 5 , the pressure at state 5 is p 5 , the reduced pressure at state 5 is p ′ r 5 and the reduced pressure at state 4 is p ′ r 4 . Write the expression for the velocity at the nozzle exit for ideal case. ( V 5 ) s = 2 ( h ′ 4 − h ′ 5 ) (II) Here, the velocity at the nozzle exit for ideal case is ( V 5 ) s , the specific enthalpy at state 4 is h ′ 4 and the specific enthalpy at state 5 is h ′ 5 . Write the expression for the velocity at the nozzle exit. V 5 = η N ( V 5 ) s (III) Here, the velocity at the nozzle exit is V 5 and the efficiency of the nozzle is η N . Conclusion: Refer to table A-22E “ideal gas properties of air” to obtain the specific enthalpy and reduced pressure at temperature T ′ 4 = 2200 ° R as 560.59 Btu / lb and 256.6 . Substitute 57.61 lbf / in 2 for p 4 , 256.6 for p ′ r 4 and 9 lbf / in 2 for p 5 in Equation (I). p ′ r 5 = ( 9 lbf / in 2 57.61 lbf / in 2 ) ( 256

Fundamentals of Engineering Thermodynamics

8th Edition

ISBN: 9781118832301

Author: SHAPIRO

Publisher: JOHN WILEY+SONS,INC.-CONSIGNMENT

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Chapter 9.14, Problem 89P

To determine

The velocity at nozzle exit.

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Chapter 9.14, Problem 88P

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Chapter 9 Solutions

Fundamentals of Engineering Thermodynamics

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