(a) Explanation Write the expression for the specific enthalpy at state 2. h 2 = h 1 + V 1 2 2 (I) Here, the specific enthalpy at state 2 is h 2 , the specific volume at state a is V 1 and the specific enthalpy at state 1is h 1 . Write the expression for the pressure at state 2. p 2 = ( p r 2 p r 1 ) p 1 (II) Here, the pressure at state 1 is p 1 , the pressure at state 2 is p 2 , the reduced pressure at state 1 is p r 1 and the reduced pressure at state 2 is p r 2 . Conclusion: Refer to table A-22 “ideal gas properties of air” to obtain the specific enthalpy and reduced pressure at temperature T 1 = 580 K as 219.97 kJ / kg and 0.4690 . Substitute 219.97 kJ / kg for h 1 , 855.6 m / s for V 1 in Equation (I). h 2 = ( 219.97 kJ / kg ) + ( 855.6 m / s ) 2 2 = ( 219 (b) To determine The velocity at nozzle exit.

Fundamentals of Engineering Thermodynamics

8th Edition

ISBN: 9781118832301

Author: SHAPIRO

Publisher: JOHN WILEY+SONS,INC.-CONSIGNMENT

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Chapter 9.14, Problem 91P

(a)

To determine

The pressure at diffuser exit.

(b)

To determine

The velocity at nozzle exit.

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Chapter 9.14, Problem 90P

Chapter 9.14, Problem 92P

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Chapter 9 Solutions

Fundamentals of Engineering Thermodynamics

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