Organic Chemistry
Organic Chemistry
2nd Edition
ISBN: 9781118452288
Author: David R. Klein
Publisher: WILEY
Question
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Chapter 9.10, Problem 33CC

(a)

Interpretation Introduction

Interpretation:

Products should be drawn for the given reactions based on their reagents.

Concept introduction:

  • Syn-dihydroxylation: syn- dihydroxylation is a process of adding two –OH groups from the same plane to the alkene.
  • Trans-dihydroxylation: trans- dihydroxylation is a process of adding two –OH groups from different planes to the alkene

To find: the products during the syn-dihydroxylation of the trans-2-butene.

(b)

Interpretation Introduction

Interpretation:

Products should be drawn for the given reactions based on their reagents.

Concept introduction:

  • Syn-dihydroxylation: syn- dihydroxylation is a process of adding two –OH groups from the same plane to the alkene.
  • Trans-dihydroxylation: trans- dihydroxylation is a process of adding two –OH groups from different planes to the alkene

To find: the products during the anti-hydroxylation of the cis-2-butene.

(c)

Interpretation Introduction

Interpretation:

Products should be drawn for the given reactions based on their reagents.

Concept introduction:

  • Syn-dihydroxylation: syn- dihydroxylation is a process of adding two –OH groups from the same plane to the alkene.
  • Trans-dihydroxylation: trans- dihydroxylation is a process of adding two –OH groups from different planes to the alkene

(d)

Interpretation Introduction

Interpretation:

Products should be drawn for the given reactions based on their reagents.

Concept introduction:

  • Syn-dihydroxylation: syn- dihydroxylation is a process of adding two –OH groups from the same plane to the alkene.
  • Trans-dihydroxylation: trans- dihydroxylation is a process of adding two –OH groups from different planes to the alkene

To find: the products during the anti-hydroxylation of the cis-2-butene.

(e)

Interpretation Introduction

Interpretation:

Products should be drawn for the given reactions based on their reagents.

Concept introduction:

  • Syn-dihydroxylation: syn- dihydroxylation is a process of adding two –OH groups from the same plane to the alkene.
  • Trans-dihydroxylation: trans- dihydroxylation is a process of adding two –OH groups from different planes to the alkene

To find: the products during the syn-dihydroxylation of the trans-2-butene.

(f)

Interpretation Introduction

Interpretation:

Products should be drawn for the given reactions based on their reagents.

Concept introduction:

  • Syn-dihydroxylation: syn- dihydroxylation is a process of adding two –OH groups from the same plane to the alkene.
  • Trans-dihydroxylation: trans- dihydroxylation is a process of adding two –OH groups from different planes to the alkene

To find: the products during the anti-hydroxylation of the cis-2-butene.

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Instructions: Complete the questions in the space provided. Show all your work 1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure the initial reaction rate and the starting concentrations of the reactions for 4 trials. BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l) Initial rate Trial [BrO3] [H*] [Br] (mol/L) (mol/L) | (mol/L) (mol/L.s) 1 0.10 0.10 0.10 8.0 2 0.20 0.10 0.10 16 3 0.10 0.20 0.10 16 4 0.10 0.10 0.20 32 a. Based on the above data what is the rate law expression? b. Solve for the value of k (make sure to include proper units) 2. The proposed reaction mechanism is as follows: i. ii. BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq) HBrO³ (aq) + H* (aq) → H₂BrO3* (aq) iii. H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l) [Fast] [Medium] [Slow] iv. Br₂O₂ (aq) + 4H*(aq) + 4Br‍(aq) → 3Br₂ (l) + H2O (l) [Fast] Evaluate the validity of this proposed reaction. Justify your answer.

Chapter 9 Solutions

Organic Chemistry

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