Explanation Calculation: Divide the circular section into number of identical circular sectors. The sections are approximated by isosceles triangles. Large number of sectors approximate dimension of one of the isosceles triangle is shown below. Sketch the circular sector as shown in Figure 1. Refer to problem 9.28. The polar moment of inertia ( J O ) is b h 48 ( 12 h 2 + b 2 ) . Sketch the triangle section as shown in Figure 2. Refer to Figure 2. b = r Δ θ And h = r Find the polar moment of inertia sector as shown below: ( Δ J O ) sector ≃ 1 48 ( b ) h [ J O ] (1) Here, b is the width of section, J O is polar moment of inertia, and h is height of section. Substitute r Δ θ for b , r for h , and b h 48 ( 12 h 2 + b 2 ) for J O in Equation (1). ( Δ J O ) sector ≃ 1 48 ( r Δ θ ) r [ b h 48 ( 12 h 2 + b 2 ) ] = 1 48 r 4 Δ θ [ ( 12 + Δ θ 2 ) ] (2) Differentiate Equation (2) with respect to θ . d J O d θ = lim Δ θ → 0 ( Δ J O Δ θ ) (3) Substitute 1 48 r 4 Δ θ [ ( 12 + Δ θ 2 ) ] for ( Δ J O ) sector in Equation (3)

Connect 1 Semester Access Card for Vector Mechanics for Engineers: Statics and Dynamics

11th Edition

ISBN: 9781259639272

Author: Ferdinand P. Beer, E. Russell Johnston Jr., David Mazurek, Phillip J. Cornwell, Brian Self

Publisher: McGraw-Hill Education

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Moment of Inertia

Inertia can be termed as a resistance offered by a body to change its state. A rigid body initially at rest will apply resistance when acted by an external force that tends to change its state of rest or velocity, or a body initially at motion will provi…

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Chapter 9.1, Problem 9.29P

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Prove the centroidal polar moment of inertia of a circular area of radius r is πr42.

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Chapter 9.1, Problem 9.28P

Chapter 9.1, Problem 9.30P

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Connect 1 Semester Access Card for Vector Mechanics for Engineers: Statics and Dynamics

Ch. 9.1 - 9.1 through 9.4 Determine by direct integration...Ch. 9.1 - 9.1 through 9.4 Determine by direct integration...Ch. 9.1 - Prob. 9.3P Ch. 9.1 - Prob. 9.4P Ch. 9.1 - 9.5 through 9.8 Determine by direct integration...Ch. 9.1 - 9.5 through 9.8 Determine by direct integration...Ch. 9.1 - Prob. 9.7P Ch. 9.1 - Prob. 9.8P Ch. 9.1 - 9.9 through 9.11 Determine by direct integration...Ch. 9.1 - Prob. 9.10P

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Prove the centroidal polar moment of inertia of a circular area of radius r is π r 4 2 .

Solution Summary: The author calculates the centroidal polar moment of inertia of a circular area of radius r. The sections are approximated by isosceles triangles.

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Prove the centroidal polar moment of inertia of a circular area of radius r is πr42.

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