Explanation In presence of oxygen ( O 2 ) a combustion reaction will produce CO 2 and H 2 O . The unbalanced chemical equation is: C 5 H 12 O + O 2 → CO 2 + H 2 O To balance the equation the number of atoms on the products side must be equal to the number of atoms on the reactants side. There are 5 carbon atoms on the reactants side so there must be 5 carbon atoms on the products side, put a 5 on CO 2 : C 5 H 12 O + O 2 → 5CO 2 + H 2 O There are 12 hydrogen atoms on the reactants side so there must be 12 hydrogen atoms on the products side, put a 6 on H 2 O: C 5 H 12 O + O 2 → 5CO 2 + 6H 2 O Finally put 15 2 on O 2 to get the balanced equation: C 5 H 12 O + 15 2 O 2 → 5CO 2 + 6H 2 O Formula used: ΔH rxn = H f o (products) − H f o (reactants) Calculation: The standard enthalpy of formation of O 2 is considered to have a value of zero

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Chapter 9, Problem 9.99SP

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To determine:

The combustion reaction for C5H12O and standard heat of combustion in kJ.

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Chapter 9, Problem 9.98SP

Chapter 9, Problem 9.100SP

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The combustion reaction for C 5 H 12 O and standard heat of combustion in kJ .

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To determine: The combustion reaction for C5H12O and standard heat of combustion in kJ.

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Chapter 9 Solutions

To determine:

The combustion reaction for C5H12O and standard heat of combustion in kJ.