The balanced reaction for the combustion of liquid ethanol should be identified. Concept introduction: Combustion reaction takes place in presence of oxygen and results in the production of carbon dioxide and water. When the number of different atoms of elements in the product side is equal to that of reactants side in a chemical equation, these types of reactions are said to be a balanced reaction.
The balanced reaction for the combustion of liquid ethanol should be identified. Concept introduction: Combustion reaction takes place in presence of oxygen and results in the production of carbon dioxide and water. When the number of different atoms of elements in the product side is equal to that of reactants side in a chemical equation, these types of reactions are said to be a balanced reaction.
The balanced reaction for the combustion of liquid ethanol should be identified.
Concept introduction:
Combustion reaction takes place in presence of oxygen and results in the production of carbon dioxide and water.
When the number of different atoms of elements in the product side is equal to that of reactants side in a chemical equation, these types of reactions are said to be a balanced reaction.
(b)
Interpretation Introduction
Interpretation:
Combustion energy should be identified.
Concept introduction: The energy for combustion can be determined by subtracting the enthalpy of formation of product from the energy of reactant as follows:
(2 ECO2+ 3 EH2O)–( EEtOH+ EO2)
(c)
Interpretation Introduction
Interpretation:
Energy in kJ /g should be identified.
Concept introduction: Combustion enthalpy in kJ/ g can be determined by dividing the energy with a molar mass of ethanol as follows: Combustion enthalpy =− 1366.7 / M
(d)
Interpretation Introduction
Interpretation:
Energy in kJ /mL should be identified.
Concept introduction: Multiplying the energy with the density provides the energy with kJ /mL as follows:
Rank the labeled protons (Ha-Hd) in order of increasing acidity, starting with the least acidic.
НОН НЬ
OHd
Онс
Can the target compound at right be efficiently synthesized in good yield from the unsubstituted benzene at left?
?
starting
material
target
If so, draw a synthesis below. If no synthesis using reagents ALEKS recognizes is possible, check the box under the drawing area.
Be sure you follow the standard ALEKS rules for submitting syntheses.
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Note for advanced students: you may assume that you are using a large excess of benzene as your starting material.
C
:0
T
Add/Remove step
G
The following equations represent the formation of compound MX. What is the AH for the
electron affinity of X (g)?
X₂ (g) → 2X (g)
M (s) → M (g)
M (g)
M (g) + e-
AH = 60 kJ/mol
AH = 22 kJ/mol
X (g) + e-X (g)
M* (g) +X (g) → MX (s)
AH = 118 kJ/mol
AH = ?
AH = -190 kJ/mol
AH = -100 kJ/mol
a)
-80 kJ
b)
-30 kJ
c)
-20 kJ
d)
20 kJ
e)
156 kJ
Chapter 9 Solutions
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