Chapter 9, Problem 9.60SP

Interpretation Introduction

Interpretation:

enthalpy change ( $\text{ΔH}$ ) for a reaction at a constant pressure of $\text{1}.00\text{ atm}$ should be determined.

Concept introduction:

  $-\text{ w}$ = work done by the system or expansion work
  $+\text{w}$ = work done on the system or compression work
  $\text{ΔH}$is the enthalpy which is basically the heat flow at a constant pressure. It is given by the following expression:
  $\text{ΔH =ΔE+Δ(PV)}$

Given:

Internal energy ( $\text{ΔE}$ ) = $\text{44}\text{.0 kJ}$

the volume change= $\text{14}\text{.0 L}$

external pressure; $\text{P=1}\text{.0 atm}$