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Concept explainers
(a)
Interpretation:
The type of bonding present in the compound
Concept introduction:
An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the non-metal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.
A covalent bond is formed by the interaction of two non-metals. Covalent compounds are formed by the sharing of electrons between two or more atoms. A covalent bond is the strong forces of attraction between the shared pairs of electrons and the nuclei of the combining atoms.
Metallic bonds are formed between metals. A metallic bond is formed between positively charged ions in a sea of delocalized electrons.
(b)
Interpretation:
The type of bonding present in the compound
Concept introduction:
An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the non-metal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.
A covalent bond is formed by the interaction of two non-metals. Covalent compounds are formed by the sharing of electrons between two or more atoms. A covalent bond is the strong forces of attraction between the shared pairs of electrons and the nuclei of the combining atoms.
Metallic bonds are formed between metals. A metallic bond is formed between positively charged ions in a sea of delocalized electrons.
(c)
Interpretation:
The type of bonding present in
Concept introduction:
An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the non-metal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.
A covalent bond is formed by the interaction of two non-metals. Covalent compounds are formed by the sharing of electrons between two or more atoms. A covalent bond is the strong forces of attraction between the shared pairs of electrons and the nuclei of the combining atoms.
Metallic bonds are formed between metals. A metallic bond is formed between positively charged ions in a sea of delocalized electrons.
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Chapter 9 Solutions
ALEKS 360 for Silberberg Chemistry: The Molecular Nature of Matter and Change
- Nonearrow_forward3. A molecular form of "dicarbon", C2, can be generated in gas phase. Its bond dissociation energy has been determined at 599 kJ/mol. Use molecular orbital theory to explain why energy of dissociation for C₂+ is 513 kJ/mol, and that for C2² is 818 kJ/mol. (10 points)arrow_forward9.73 g of lead(IV) chloride contains enough Cl- ions to make ____ g of magnesium chloride.arrow_forward
- 6. a) C2's. Phosphorus pentafluoride PF5 belongs to D3h symmetry group. Draw the structure of the molecule, identify principal axis of rotation and perpendicular (4 points) b) assume that the principal axis of rotation is aligned with z axis, assign symmetry labels (such as a1, b2, etc.) to the following atomic orbitals of the P atom. (character table for this group is included in the Supplemental material). 3s 3pz (6 points) 3dz²arrow_forward2. Construct Lewis-dot structures, and draw VESPR models for the ions listed below. a) SiF5 (4 points) b) IOF4 (4 points)arrow_forward5. Complex anion [AuCl2]¯ belongs to Doh symmetry point group. What is the shape of this ion? (4 points)arrow_forward
- 4. Assign the following molecules to proper point groups: Pyridine N 1,3,5-triazine N Narrow_forward7. a) Under normal conditions (room temperature & atmospheric pressure) potassium assumes bcc lattice. Atomic radius for 12-coordinate K atom is listed as 235 pm. What is the radius of potassium atom under normal conditions? (3 points) b) Titanium metal crystallyzes in hcp lattice. Under proper conditions nitrogen can be absorbed into the lattice of titanium resulting in an alloy of stoichiometry TiNo.2. Is this compound likely to be a substitutional or an interstitial alloy? (Radius of Ti (12-coordinate) is 147 pm; radius of N atom is 75 pm. (3 points)arrow_forwardcan someone answer the questions and draw out the complete mechanismarrow_forward
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