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Concept explainers
(a)
Interpretation:
The bonds in the following set are to be ranked in order of increasing bond length and increasing bond strength.
Concept introduction:
A covalent bond is formed by the interaction of two nonmetals. Covalent compounds are formed by the sharing of electrons between two or more atoms. A covalent bond is the strong forces of attraction between the shared pairs of electrons and the nuclei of the combining atoms.
In the covalent bond, bond energy is the energy needed to overcome the attractive forces between the nuclei of atoms and the shared pair of electrons. Bond energy is the enthalpy change associated with breaking of bond of
The bond energy of a bond is directly related to the bond strength of a bond. Greater the bond strength of the bond more will be the bond energy of the bond and vice-versa. In the covalent bond, the strength of the bond is inversely related to the size of the atom.
Bond length is the distance between the nuclei of the atoms connected by a bond. Higher the bond strength more strong will be the bond and shorter will be the bond length.
(b)
The bonds in the following set are to be ranked in order of increasing bond length and increasing bond strength.
Concept introduction:
A covalent bond is formed by the interaction of two nonmetals. Covalent compounds are formed by the sharing of electrons between two or more atoms. A covalent bond is the strong forces of attraction between the shared pairs of electrons and the nuclei of the combining atoms.
In the covalent bond, bond energy is the energy needed to overcome the attractive forces between the nuclei of atoms and the shared pair of electrons. Bond energy is the enthalpy change associated with breaking of bond of
The bond energy of a bond is directly related to the bond strength of a bond. Greater the bond strength of the bond more will be the bond energy of the bond and vice-versa. In the covalent bond, the strength of the bond is inversely related to the size of the atom.
Bond length is the distance between the nuclei of the atoms connected by a bond. Higher the bond strength more strong will be the bond and shorter will be the bond length.
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Chapter 9 Solutions
ALEKS 360 for Silberberg Chemistry: The Molecular Nature of Matter and Change
- 1. Consider a pair of elements with 2p and 4p valence orbitals (e.g., N and Se). Draw their (2p and 4p AO's) radial probability plots, and sketch their angular profiles. Then, consider these orbitals from the two atoms forming a homonuclear л-bond. Which element would have a stronger bond, and why? (4 points)arrow_forwardWrite the reaction and show the mechanism of the reaction. Include the mechanism for formation of the NO2+ 2. Explain, using resonance structures, why the meta isomer is formed. Draw possible resonance structures for ortho, meta and para.arrow_forwardNonearrow_forward
- 3. A molecular form of "dicarbon", C2, can be generated in gas phase. Its bond dissociation energy has been determined at 599 kJ/mol. Use molecular orbital theory to explain why energy of dissociation for C₂+ is 513 kJ/mol, and that for C2² is 818 kJ/mol. (10 points)arrow_forward9.73 g of lead(IV) chloride contains enough Cl- ions to make ____ g of magnesium chloride.arrow_forward6. a) C2's. Phosphorus pentafluoride PF5 belongs to D3h symmetry group. Draw the structure of the molecule, identify principal axis of rotation and perpendicular (4 points) b) assume that the principal axis of rotation is aligned with z axis, assign symmetry labels (such as a1, b2, etc.) to the following atomic orbitals of the P atom. (character table for this group is included in the Supplemental material). 3s 3pz (6 points) 3dz²arrow_forward
- 2. Construct Lewis-dot structures, and draw VESPR models for the ions listed below. a) SiF5 (4 points) b) IOF4 (4 points)arrow_forward5. Complex anion [AuCl2]¯ belongs to Doh symmetry point group. What is the shape of this ion? (4 points)arrow_forward4. Assign the following molecules to proper point groups: Pyridine N 1,3,5-triazine N Narrow_forward
- 7. a) Under normal conditions (room temperature & atmospheric pressure) potassium assumes bcc lattice. Atomic radius for 12-coordinate K atom is listed as 235 pm. What is the radius of potassium atom under normal conditions? (3 points) b) Titanium metal crystallyzes in hcp lattice. Under proper conditions nitrogen can be absorbed into the lattice of titanium resulting in an alloy of stoichiometry TiNo.2. Is this compound likely to be a substitutional or an interstitial alloy? (Radius of Ti (12-coordinate) is 147 pm; radius of N atom is 75 pm. (3 points)arrow_forwardcan someone answer the questions and draw out the complete mechanismarrow_forwardPlease help, draw and me the proper mechanisms.arrow_forward
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