9.54 The phase change between graphite and diamond is difficult to observe directly. Both substances can be hurned, however. From these equations, calculate Δ H ° for the conversion of diamond into graphite. C ( s , graphite ) + O 2 ( g ) → CO 2 ( g ) Δ H ° = -393.51 kJ C ( s , diamond ) + O 2 ( g ) → CO 2 ( g ) Δ H ° = -395.94 kJ
9.54 The phase change between graphite and diamond is difficult to observe directly. Both substances can be hurned, however. From these equations, calculate Δ H ° for the conversion of diamond into graphite. C ( s , graphite ) + O 2 ( g ) → CO 2 ( g ) Δ H ° = -393.51 kJ C ( s , diamond ) + O 2 ( g ) → CO 2 ( g ) Δ H ° = -395.94 kJ
Solution Summary: The author explains that Hess's law allows us to calculate the heat of reaction for any reaction that occurs at standard conditions.
9.54 The phase change between graphite and diamond is difficult to observe directly. Both substances can be hurned, however. From these equations, calculate
Δ
H
°
for the conversion of diamond into graphite.
Draw the major product of this reaction. Ignore inorganic
byproducts.
Incorrect, 3 attempts remaining
1. excess Br2, NaOH
2. neutralizing workup
Q
Given the electrode Pt | Ag | Ag+ (aq), describe it.
At 25°C, the reaction Zn2+ + 2e ⇄ Zn has a normal equilibrium potential versus the saturated calomel electrode of -1.0048 V. Determine the normal equilibrium potential of Zn versus the hydrogen electrode.Data: The calomel electrode potential is E° = 0.2420 V versus the normal hydrogen electrode.
Chapter 9 Solutions
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