Chemistry for Today: General  Organic  and Biochemistry
Chemistry for Today: General Organic and Biochemistry
9th Edition
ISBN: 9781337514576
Author: Seager
Publisher: Cengage
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Chapter 9, Problem 9.27E

Calculate the molar concentration of OH in water solutions with the following H 3 O + molar concentrations:

a. 1.0 × 10 6

b. 4.8 × 10 4

c. 6.2 × 10 10

d. 1.4

e. 0.038

Expert Solution
Check Mark
Interpretation Introduction

(a)

Interpretation:

The molar concentration of OH in water solutions with the given H3O+ molar concentrations is to be calculated.

Concept introduction:

The water undergoes self ionization which can be represented by the reaction,

H2O(l)+H2O(l)H3O+(aq)+OH(aq)

The ionization constant of water is represented as,

K=[H3O+][OH][H2O][H2O]

The concentration of water remains constant and the self-ionization constant of water becomes,

Kw=[H3O+][OH]Kw=(1.0×107mol/L)(1.0×107mol/L)Kw=1.0×1014(mol/L)2

Answer to Problem 9.27E

The molar concentration of OH in water solutions is 1.0×108mol/L.

Explanation of Solution

The ionic product of water Kw is,

Kw=[H3O+][OH]

The value of Kw is 1.0×1014(mol/L)2.

The given H3O+ molar concentration is 1.0×106mol/L. Substitute this value in the formula for ionic product.

1.0×1014(mol/L)2=1.0×106mol/L[OH][OH]=1.0×1014(mol/L)21.0×106mol/L[OH]=1.0×108mol/L

Thus, the molar concentration of OH in water solutions is 1.0×108mol/L.

Conclusion

The molar concentration of OH in water solutions is 1.0×108mol/L.

Expert Solution
Check Mark
Interpretation Introduction

(b)

Interpretation:

The molar concentration of OH in water solutions with the given H3O+ molar concentrations is to be calculated.

Concept introduction:

The water undergoes self ionization which can be represented by the reaction,

H2O(l)+H2O(l)H3O+(aq)+OH(aq)

The ionization constant of water is represented as,

K=[H3O+][OH][H2O][H2O]

The concentration of water remains constant and the self-ionization constant of water becomes,

Kw=[H3O+][OH]Kw=(1.0×107mol/L)(1.0×107mol/L)Kw=1.0×1014(mol/L)2

Answer to Problem 9.27E

The molar concentration of OH in water solutions is 2.08×1011mol/L.

Explanation of Solution

The ionic product of water Kw is,

Kw=[H3O+][OH]

The value of Kw is 1.0×1014(mol/L)2.

The given H3O+ molar concentration is 4.8×104mol/L. Substitute this value in the formula for ionic product.

1.0×1014(mol/L)2=4.8×104mol/L[OH][OH]=1.0×1014(mol/L)24.8×104mol/L[OH]=2.08×1011mol/L

Thus, the molar concentration of OH in water solutions is 2.08×1011mol/L.

Conclusion

The molar concentration of OH in water solutions is 2.08×1011mol/L.

Expert Solution
Check Mark
Interpretation Introduction

(c)

Interpretation:

The molar concentration of OH in water solutions with the given H3O+ molar concentrations is to be calculated.

Concept introduction:

The water undergoes self ionization which can be represented by the reaction,

H2O(l)+H2O(l)H3O+(aq)+OH(aq)

The ionization constant of water is represented as,

K=[H3O+][OH][H2O][H2O]

The concentration of water remains constant and the self-ionization constant of water becomes,

Kw=[H3O+][OH]Kw=(1.0×107mol/L)(1.0×107mol/L)Kw=1.0×1014(mol/L)2

Answer to Problem 9.27E

The molar concentration of OH in water solutions is 1.61×105mol/L.

Explanation of Solution

The ionic product of water Kw is,

Kw=[H3O+][OH]

The value of Kw is 1.0×1014(mol/L)2.

The given H3O+ molar concentration is 6.2×1010mol/L. Substitute this value in the formula for ionic product.

1.0×1014(mol/L)2=6.2×1010mol/L[OH][OH]=1.0×1014(mol/L)26.2×1010mol/L[OH]=1.61×105mol/L

Thus, the molar concentration of OH in water solutions is 1.61×105mol/L.

Conclusion

The molar concentration of OH in water solutions is 1.61×105mol/L.

Expert Solution
Check Mark
Interpretation Introduction

(d)

Interpretation:

The molar concentration of OH in water solutions with the given H3O+ molar concentrations is to be calculated.

Concept introduction:

The water undergoes self ionization which can be represented by the reaction,

H2O(l)+H2O(l)H3O+(aq)+OH(aq)

The ionization constant of water is represented as,

K=[H3O+][OH][H2O][H2O]

The concentration of water remains constant and the self-ionization constant of water becomes,

Kw=[H3O+][OH]Kw=(1.0×107mol/L)(1.0×107mol/L)Kw=1.0×1014(mol/L)2

Answer to Problem 9.27E

The molar concentration of OH in water solutions is 7.14×1015mol/L.

Explanation of Solution

The ionic product of water Kw is,

Kw=[H3O+][OH]

The value of Kw is 1.0×1014(mol/L)2.

The given H3O+ molar concentration is 1.4mol/L. Substitute this value in the formula for ionic product.

1.0×1014(mol/L)2=1.4mol/L[OH][OH]=1.0×1014(mol/L)21.4mol/L[OH]=7.14×1015mol/L

Thus, the molar concentration of OH in water solutions is 7.14×1015mol/L.

Conclusion

The molar concentration of OH in water solutions is 7.14×1015mol/L.

Expert Solution
Check Mark
Interpretation Introduction

(e)

Interpretation:

The molar concentration of OH in water solutions with the given H3O+ molar concentrations is to be calculated.

Concept introduction:

The water undergoes self ionization which can be represented by the reaction,

H2O(l)+H2O(l)H3O+(aq)+OH(aq)

The ionization constant of water is represented as,

K=[H3O+][OH][H2O][H2O]

The concentration of water remains constant and the self-ionization constant of water becomes,

Kw=[H3O+][OH]Kw=(1.0×107mol/L)(1.0×107mol/L)Kw=1.0×1014(mol/L)2

Answer to Problem 9.27E

The molar concentration of OH in water solutions is 2.63×1013mol/L.

Explanation of Solution

The ionic product of water Kw is,

Kw=[H3O+][OH]

The value of Kw is 1.0×1014(mol/L)2.

The given H3O+ molar concentration is 0.038mol/L. Substitute this value in the formula for ionic product.

1.0×1014(mol/L)2=0.038mol/L[OH][OH]=1.0×1014(mol/L)20.038mol/L[OH]=2.63×1013mol/L

Thus, the molar concentration of OH in water solutions is 2.63×1013mol/L.

Conclusion

The molar concentration of OH in water solutions is 2.63×1013mol/L.

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Chapter 9 Solutions

Chemistry for Today: General Organic and Biochemistry

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