Determination of lattice energy of K C l using Born-Haber cycle has to be explained. The law for the basis of this method has to be outlined. Concept Introduction: Born-Haber cycle is based on Hess’s law to calculate the lattice enthalpy of ionic compounds and deals with energy changes in formation of ionic compounds. The energy released when gaseous state ions of unlike charges that are infinitely farther apart combine to form a stable ionic solid is called Lattice energy . Conversely, the energy required to break the electrostatic force of attraction between the ions of unlike charges in the ionic solid and revert them to gaseous state is also termed as Lattice energy of an ionic solid. Hess’s law is applied to calculate the enthalpy changes in a reaction. According to Hess’s law – “The overall enthalpy change of a reaction is equal to the sum of the enthalpy changes involving in each and every individual steps in the reaction.” Thus if a reaction involves ‘n’ steps then enthalpy change Δ H ° of the reaction is, Δ H ° = Δ H 1 ° + Δ H 2 ° + Δ H 3 ° .... + Δ H n °

Question

Want to see the full answer?

Answer 1

Question

Chapter 9, Problem 9.22QP

Interpretation Introduction

Interpretation:

Determination of lattice energy of KCl using Born-Haber cycle has to be explained. The law for the basis of this method has to be outlined.

Concept Introduction:

Born-Haber cycle is based on Hess’s law to calculate the lattice enthalpy of ionic compounds and deals with energy changes in formation of ionic compounds.

The energy released when gaseous state ions of unlike charges that are infinitely farther apart combine to form a stable ionic solid is called Lattice energy. Conversely, the energy required to break the electrostatic force of attraction between the ions of unlike charges in the ionic solid and revert them to gaseous state is also termed as Lattice energy of an ionic solid.

Hess’s law is applied to calculate the enthalpy changes in a reaction. According to Hess’s law – “The overall enthalpy change of a reaction is equal to the sum of the enthalpy changes involving in each and every individual steps in the reaction.” Thus if a reaction involves ‘n’ steps then enthalpy change ΔH° of the reaction is,

ΔH°= ΔH1°+ΔH2°+ΔH3°....+ΔHn°

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

B 1 of 2 Additional problems in preparation to Midterm #1: 1.) How can the following compounds be prepared using Diels-Alder reaction: CH3 O CN (a) (b) CN CH3 2.) What is the missing reagent in the shown reaction? H3C + ? H3C H3C CN H3C ''CN (၁) H 3.) Write the products 1,2-addition and 1,4-addition of DBr to 1,3-cyclohexadiene. Remember, D is deuterium, a heavy isotope of hydrogen. It reacts exactly like hydrogen. 4.) In the shown reaction, which will be the kinetic product and which will be the thermodynamic product? H3C CI H3C HCI H3C + 5.) Which of the following molecules is aromatic? (a) (b) (c) H 6.) Which of the following molecules is aromatic? (a) (b) (c) 7.) Write the mechanism for the shown reaction. + Ха AICI 3 CI 8.) Suggest reagents that would convert benzene into the shown compounds. CI NO2 -8-6-6-8-a (a) (b) (c) (d) (e) (a) SO3H Br

The number of 2sp^2 hybridized atoms in is: A. 8; B. 6; C.4; D.2; E.0;

The highest boiling compound from among the following isA. 2-methylheptane; B. 3-methylheptane; C. 2,2-dimethylhexane;D. octane; E. 2,2,3-trimethylpentane