Interpretation:
Precipitate protein is obtained by treating 5.00 mL sample of blood with trichloroacetic acid. The final solution has pH of 3 and this solution is extracted with two portions of 5 ml of methyl isobutyl
Concept introduction:
Beer Lambert law gives the relationship between absorbance and concentration of a sample. For the calculation of concentration, the following the equation of straight line as follows:
Where,
y = absorbance
x = concentration of sample
m is slope of graph plotted between absorbance and concentration of the sample.
And,
C is intercept of the graph.
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Chapter 9 Solutions
Principles of Instrumental Analysis
- Water sample from different river water was subjected to a qualitative alkaline analysis by titrating against 0.1250 MHC1 and using phenolphthalein and bromocresol green end point. The table below shows the volumes of acid needed to titrate 25.00-mL portions of each sample and their corresponding end point, separately. Use this information to deduce the composition of the solutions. Calculate the molar concentration of each solute. Volume (mL) Phenolphthalein end Bromocresol green Solute identity concentration end point Volume (mL) Molar Sample point 22.40 of solute/s 1 22.41 2 0.00 33.40 3 15.67 42.13 4 29.64 36.42arrow_forwardThe Merck Index indicates that 10 mg of guanidine,CH5N3, may be administered for each kilogram of bodymass in the treatment of myasthenia gravis. The nitrogenin a 4-tablet sample that had a total mass of 7.50 g wasconverted to ammonia by a Kjeldahl digestion, followedby distillation into 100.0 mL of 0.1750 M HCl. Theanalysis was completed by titrating the excess acid with11.37 mL of 0.1080 M NaOH. How many of thesetablets represent a proper dose for a patient who weighs(a) 100 lb, (b) 150 lb, and (c) 275 lb?arrow_forwardA double indicator analysis of a soda ash sample was performed. The student weighed 0.4375 g of the soda ash sample and dissolved it to make 100.0 mL solution. The students then took a 25 mL aliquot of the sample solution, then added 25 mL H2O and performed double indicator titration. The phenolphthalein endpoint required 10.27 mL 0.04027 M HCl titrant. The sample was further titrated using Methyl Orange and took a total of 15.97 mL of the titrant to reach the endpoint. Given that the molar weight of Na2CO3 - 105.99 g/mol, NaHCO3 = 84.007 g/mol, and NaOH - 39.997 g/mol answer the following: a. What are the components of the soda ash sample? (The constituents of the sample came from Na2CO3, NaHCO3, and NaOH). b. What are the moles of each component in the titrated 25 mL aliquot? c. What is the percent composition in (% w/w) of each component in the soda ash sample?arrow_forward
- 3arrow_forwardA 1.5000-g sample of cereals was analyzed for nitrogen using the Kjeldahl procedure. The receiving flask contained 69 mL of 0.02 M HCl. After the ammonia was collected, the solution was titrated with 0 M NaOH, requiring 11.72 mL to reach the methyl red endpoint. Calculate and percent protein in the sample (f=5.70). Ans. in 3 SFsarrow_forwardThe Kjedahl procedure was used to analyze 256 µL of a solution containing 37.9 mg protein/mL. The liberated NH3 was collected in 5.00 mL of 0.033 6 M HCl, and the remaining acid required 6.34 mL of 0.010 M NaOH for complete titration. What is the weight percent of nitrogen in the protein? wt%arrow_forward
- A 567.9 mg sample containing Na2CO3, NaHCO3 , NaOH and inert material was dissolved and titrated with 0.1002 M HCl. The titration required 24.30 mL to reach the phenolphthalein endpoint and an additional 38.67 mL to reach the methyl red endpoint. Determine the composition of the sample and the % of each titrated component.arrow_forward0,0585g Na2C204 10 ml 'to adjust KMN04 solution prepared as 0,1M distilled water, 2 M H2SO4 was added, heated and 8.4 ml titrant has been spent. Calculate the true concentration of potassium permanganate accordingly.arrow_forwardFor Qualitative analysis of amines and amine Unknown, provide chemical structures.arrow_forward
- The following data were obtained from the spectrophotometric titration of Cu(II) and Ca(II) in an unknown solution. A 25.00 mL aliquot of the unknown was taken to which 50.0 mL of ethanolamine buffer and 25.0 mL of distilled water were added. The solution was then titrated with standard 0.2508 M EDTA solution. Plot the recorded data, absorbance against volume of EDTA in mL. Correct the absorbance for volume changes. Calculate the number of moles of Ca(II) and Cu(II) in the unknown sample. Vol of Titrant, mL Vol of Titrant, mL Abs Abs 0.0 0.416 12.5 0.886 2.0 0.415 13.0 0.923 4.0 0.409 13.5 0.958 6.0 0.416 14.0 0.979 8.0 0.535 14.5 0.969 10.0 0.690 15.0 0.971 11.0 0.770 15.5 0.964 12.0 0.840arrow_forwardTonic water (20.0 mL) was added into each of two volumetric flasks (100 mL). The first flask was made up to volume with deionised water and produced an absorbance of 0.200. To the second flask was added an aliquot (20.0 mL) of a quinine standard solution (20.0 ppm) and after being made up to volume this produced an absorbance of 0.400. What is the concentration of quinine in the tonic water? a. 8.00 ppm b. 800 ppm С. 40.0 ppm d. 400 ppm е. 20.0 ppmarrow_forwardComplexometric titrations are generally conducted to determine divalent cations. The most important applications are the titration of calcium and magnesium with EDTA. (a) A supplement tablet containing about 300.00 mg of calcium ion was dissolved, filtered, and diluted to 100.00 ml volume. Several 2.00 ml samples of the total solution were titrated with 0.0100 M EDTA solution. The mean corrected titration volume was 13.65 mL. Calculate the calcium content of the supplement tablet in mg units. (b) A sample of Epsom Salt of mass 0.7567 g was dissolved uniformly in distilled water in a 250.00 mL volumetric flask. Portions of the magnesium ion solution of volume 10.00 mL were titrated using a 0.01000 M solution of EDTA. The mean corrected titration volume was 12.25 ml. Calculate the percentage by mass (% w / w) of the magnesium in the Epsom Salt sample. (c) A 100.00 mL sample of tap water was titrated with 0.0100 M EDTA solution. The mean corrected titration volume was 14.80 mL. Determine…arrow_forward