
Concept explainers
(a)
Interpretation:
The hybridization and geometry around each sulfur atom in
Concept introduction:
Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that exist on each bonded atom.
Lewis dot structure is also known as Lewis dot formula or electron dot structure. The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration
(b)
Interpretation:
The double bond energy in S=S in
Concept introduction:
The Gibb’s equation of
(c)
Interpretation:
Molecular orbital description of the bonding in S2 and whether S2 is paramagnetic or diamagnetic in nature needs to be determined.
Concept introduction:
The molecular orbital theory explained the bonding, magnetic and spectral properties of a molecule. It is based on the formation of molecular orbitals by the combination of atomic orbitals. On the basis of energy and stability these molecular orbitals can be further classified into three types:
- Bonding molecular orbitals (BMO): They have lesser energy than atomic orbital, therefore, more stable compare to atomic orbital.
- Antibonding molecular orbitals (ABMO): They have higher energy than atomic orbital therefore less stable compare to atomic orbital.
- Non-bonding molecular orbitals (NBMO): They have the same energy as atomic orbital.
A molecular orbital diagram represents the distribution of electrons in different molecular orbitals in increasing order of their energy. Hence lower energy molecular orbitals occupy first then only electron moves in higher energy orbitals.

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Chapter 9 Solutions
CHEMISTRY-MASTERINGCHEMISTRY W/ETEXT
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- What does the phrase 'fit for purpose' mean in relation to analytical chemistry? Please provide examples too.arrow_forwardFor each of the substituted benzene molecules below, determine the inductive and resonance effects the substituent will have on the benzene ring, as well as the overall electron-density of the ring compared to unsubstituted benzene. Molecule Inductive Effects Resonance Effects Overall Electron-Density × NO2 ○ donating O donating O withdrawing O withdrawing O electron-rich electron-deficient no inductive effects O no resonance effects O similar to benzene E [ CI O donating withdrawing O no inductive effects Explanation Check ○ donating withdrawing no resonance effects electron-rich electron-deficient O similar to benzene © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accesarrow_forwardUnderstanding how substituents activate Rank each of the following substituted benzene molecules in order of which will react fastest (1) to slowest (4) by electrophilic aromatic substitution. Explanation HN NH2 Check X (Choose one) (Choose one) (Choose one) (Choose one) © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Aarrow_forward
- Identifying electron-donating and electron-withdrawing effects on benzene For each of the substituted benzene molecules below, determine the inductive and resonance effects the substituent will have on the benzene ring, as well as the overall electron-density of the ring compared to unsubstituted benzene. Inductive Effects Resonance Effects Overall Electron-Density Molecule CF3 O donating O donating O withdrawing O withdrawing O no inductive effects O no resonance effects electron-rich electron-deficient O similar to benzene CH3 O donating O withdrawing O no inductive effects O donating O withdrawing Ono resonance effects O electron-rich O electron-deficient O similar to benzene Explanation Check Х © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Centerarrow_forward* Hint: Think back to Chem 1 solubility rules. Follow Up Questions for Part B 12. What impact do the following disturbances to a system at equilibrium have on k, the rate constant for the forward reaction? Explain. (4 pts) a) Changing the concentration of a reactant or product. (2 pts) b) Changing the temperature of an exothermic reaction. (2 pts) ofarrow_forwardDraw TWO general chemical equation to prepare Symmetrical and non-Symmetrical ethers Draw 1 chemical reaction of an etherarrow_forward
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