Explanation Given info : The tension in the rod is 5.8 × 10 3 N , the radius of the rod is 0.20 cm , length of aluminium rod is 1.3 m , length of the copper rod is 2.6 m , Young’s modulus of aluminium is 7.0 × 10 10 Pa , and Young’s modulus of the copper is 11 × 10 10 Pa . Explanation : The total elongation of the rod is the individual elongation of the rods contains aluminium and copper that is Δ L rod = Δ L Al + Δ L Cu = ( F ( L 0 ) Al / A Y Al ) + ( F ( L 0 ) Cu / A Y Cu ) . The cross-sectional area of the rod is A = π r 2 . The formula for the elongation of the rod is, Δ L rod = F π r 2 ( ( L 0 ) Al Y Al + ( L 0 ) Cu Y Cu ) F is the force of tension. r is radius of the rod. ( L 0 ) Al is length of aluminium. ( L 0 ) Cu is length of copper

11th Edition

ISBN: 9781305952300

Author: Raymond A. Serway, Chris Vuille

Publisher: Cengage Learning

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Variation of pressure

From the equation of pressure, pressure is directly proportional to the applied force.

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Chapter 9, Problem 75P

To determine

The elongation of the rod.

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Chapter 9 Solutions

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The elongation of the rod.

Solution Summary: The author explains that the elongation of the rod is 1.9cm.

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The elongation of the rod.

Chapter 9 Solutions