EBK INTRODUCTION TO CHEMISTRY
5th Edition
ISBN: 9781260162165
Author: BAUER
Publisher: MCGRAW HILL BOOK COMPANY
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Chapter 9, Problem 67QP
Interpretation Introduction
Interpretation:
Gay Lussac’s law is to be determined.
Concept Introduction:
At constant volume, increase in the temperature of a gas leads to an increase in the kinetic energy of the gas particles.. The particles of gas collide with each other and to the wall of the container with much higher force than before. Hence the pressure exerted on the wall of the container also increases. The temperature is thus directly proportional to the pressure of the gas at constant volume.
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From the following potentials, calculate the activity of Cl- in saturated KCl.
E0 (calomel electrode)= 0.268 V
E (calomel electrode, saturated KCl)= 0.241 V
Calculate the voltage of each of the following cells.
a) Fe(s)/Fe2+ (1.55 x 10-2 M)//Cu2+ (6.55 x 10-3 M)/Cu(s)
b) Pt, H2 (0.255 bar)/HCl (4.55 x 10-4 M), AgCl (sat'd)/Ag
Fe2+ +2e- = Fe E0= -0.44 V
Cu2+ + 2e- = Cu E0= 0.337 V
Ag+ + e- = Ag E0= 0.799 V
AgCl(s) + e- = Ag(s) + Cl- E0= 0.222 V
2H+ + 2e- = H2 E0= 0.000 V
A solution contains 0.097 M Ce3+, 1.55x10-3 M Ce4+, 1.55x10-3 M Mn2+, 0.097 M MnO4-, and 1.00 M HClO4 (F= 9.649 x 104 C/mol).
a) Write a balanced net reaction that can occur between species in this solution.
b) Calculate deltaG0 and K for the reaction.
c) Calculate E and deltaG for the conditions given.
Ce4+ + e- = Ce3+ E0= 1.70 V
MnO4- + 8H+ + 5e- = Mn2+ + 4H2O E0= 1.507 V
Chapter 9 Solutions
EBK INTRODUCTION TO CHEMISTRY
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