Concept explainers
(a)
Interpretation:
The calculation of the number of moles and volume of
(a)
Explanation of Solution
Where, R is the universal gas constant and its values changes in accordance with the units of pressure, volume and temperature.
The given mass of
For
The number of moles of gases is calculated using the given formula:
Here,
Substitute
Recall equation (1),
Substitute
(b)
Interpretation:
The calculation of the number of moles and volume of
(b)
Explanation of Solution
The conversion factor of temperature from Celsius to Kelvin is as follows:
For
The number of moles of gases is calculated using the given formula:
Here,
Substitute
Recall equation (1)
Substitute
(c)
Interpretation:
The calculation of the number of moles and volume of
(c)
Explanation of Solution
The conversion factor of temperature from Celsius to Kelvin is as follows:
For
The number of moles of gases is calculated using the given formula:
Here,
Substitute
Recall equation (1),
Substitute
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Chapter 9 Solutions
EBK INTRODUCTION TO CHEMISTRY
- Raoul Pictet, the Swiss physicist who first liquefied oxygen, attempted to liquefy hydrogen. He heated potassium formate, KCHO2, with KOH in a closed 2.50-Lvessel. KCHO2(s)+KOH(s)K2CO3(s)+H2(g) If 75.0 g of potassium formate reacts in a 2.50-L vessel, which was initially evacuated, what pressure of hydrogen will be attained when the temperature is finally cooled to 25C? Use the preceding chemical equation and ignore the volume of solid product.arrow_forwardLiquid oxygen was first prepared by heating potassium chlorate, KClO3, in a closed vessel to obtain oxygen at high pressure. The oxygen was cooled until it liquefied. 2KClO3(s)2KCl(s)+3O2(g) If 171 g of potassium chlorate reacts in a 2.70-L vessel, which was initially evacuated, what pressure of oxygen will be attained when the temperature is finally cooled to 25C? Use the preceding chemical equation and ignore the volume of solid product.arrow_forwardPotassium peroxide is used to absorb the CO2 produced by the people in a space vehicle. 2K2O2(s)+2CO2(g)2K2CO3(s)+O2(g)If a person at rest exhales 3.0 L of air per minute and CO2 is 3.4% (by volume) of exhaled air, how many grams of K2O2 are needed per person for a five-day trip. Assume a temperature of 250 and 728 mm Hg pressure.arrow_forward
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