Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)
10th Edition
ISBN: 9780073398204
Author: Richard G Budynas, Keith J Nisbett
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Textbook Question
Chapter 9, Problem 3P
9–1 to 9–4 The figure shows a horizontal steel bar of thickness h loaded in steady tension and welded to a vertical support. Find the load F that will cause an allowable shear stress, τallow, in the throats of the welds.
Problem Number | b | d | h | τallow |
9–1 | 50 mm | 50 mm | 5 mm | 140 Mpa |
9–2 | 2 in | 2 in |
|
25 kspi |
9–3 | 50 mm | 30 mm | 5 mm | 140 Mpa |
9–4 | 4 in | 2 in |
|
25 kpsi |
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
You are working as an engineer in a bearing systems design company. The flow of
lubricant inside a hydrodynamic bearing (p = 0.001 kg m-1 s-1) can be approximated
as a parallel, steady, two-dimensional, incompressible flow between two parallel plates.
The top plate, representing the moving part of the bearing, travels at a constant speed,
U, while the bottom plate remains stationary (Figure Q1). The plates are separated by
a distance of 2h = 1 cm and are W = 20 cm wide. Their length is L = 10 cm. By
applying the above approximations to the Navier-Stokes equations and assuming that
end effects can be neglected, the horizontal velocity profile can be shown to be
y = +h
I
2h = 1 cm
x1
y = -h
u(y)
1 dP
2μ dx
-y² + Ay + B
moving plate
stationary plate
U
2
I2
L = 10 cm
Figure Q1: Flow in a hydrodynamic bearing. The plates extend a width, W = 20 cm,
into the page.
Question 1
You are working as an engineer in a bearing systems design company. The flow of
lubricant inside a hydrodynamic bearing (µ = 0.001 kg m¯¹ s¯¹) can be approximated
as a parallel, steady, two-dimensional, incompressible flow between two parallel plates.
The top plate, representing the moving part of the bearing, travels at a constant speed,
U, while the bottom plate remains stationary (Figure Q1). The plates are separated by
a distance of 2h = 1 cm and are W = 20 cm wide. Their length is L = 10 cm. By
applying the above approximations to the Navier-Stokes equations and assuming that
end effects can be neglected, the horizontal velocity profile can be shown to be
1 dP
u(y)
=
2μ dx
-y² + Ay + B
y= +h
Ꮖ
2h=1 cm
1
x1
y = −h
moving plate
stationary plate
2
X2
L = 10 cm
Figure Q1: Flow in a hydrodynamic bearing. The plates extend a width, W = 20 cm,
into the page.
(a) By considering the appropriate boundary conditions, show that the constants take
the following forms:
U
U
1 dP
A =…
Question 2
You are an engineer working in the propulsion team for a supersonic civil transport
aircraft driven by a turbojet engine, where you have oversight of the design for the
engine intake and the exhaust nozzle, indicated in Figure Q2a. The turbojet engine can
operate when provided with air flow in the Mach number range, 0.60 to 0.80. You are
asked to analyse a condition where the aircraft is flying at 472 m/s at an altitude of
14,000 m. For all parts of the question, you can assume that the flow path of air through
the engine has a circular cross section.
(a)
← intake
normal
shock
472 m/s
A B
(b)
50 m/s
H
472 m/s
B
engine
altitude: 14,000 m
exhaust nozzle
E
F
exit to
atmosphere
diameter: DE = 0.30 m
E
F
diameter: DF = 0.66 m
Figure Q2: Propulsion system for a supersonic aircraft.
a) When the aircraft is at an altitude of 14,000 m, use the International Standard
Atmosphere in the Module Data Book to state the local air pressure and tempera-
ture. Thus show that the aircraft speed…
Chapter 9 Solutions
Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)
Ch. 9 - 91 to 94 The figure shows a horizontal steel bar...Ch. 9 - 91 to 94 The figure shows a horizontal steel bar...Ch. 9 - 91 to 94 The figure shows a horizontal steel bar...Ch. 9 - 91 to 94 The figure shows a horizontal steel bar...Ch. 9 - 95 to 98 For the weldments of Probs. 91 to 94, the...Ch. 9 - 95 to 98 For the weldments of Probs. 91 to 94, the...Ch. 9 - 95 to 98 For the weldments of Probs. 91 to 94, the...Ch. 9 - 95 to 98 For the weldments of Probs. 91 to 94, the...Ch. 9 - 99 to 912 The materials for the members being...Ch. 9 - Prob. 10P
Ch. 9 - Prob. 11PCh. 9 - 99 to 912 The materials for the members being...Ch. 9 - 913 to 916 A steel bar of thickness h is welded to...Ch. 9 - 913 to 916 A steel bar of thickness h is welded to...Ch. 9 - 913 to 916 A steel bar of thickness h is welded to...Ch. 9 - Prob. 16PCh. 9 - Prob. 17PCh. 9 - 917 to 920 A steel bar of thickness h, to be used...Ch. 9 - 917 to 920 A steel bar of thickness h, to be used...Ch. 9 - 917 to 920 A steel bar of thickness h, to be used...Ch. 9 - Prob. 21PCh. 9 - 921 to 924 The figure shows a weldment just like...Ch. 9 - Prob. 23PCh. 9 - Prob. 24PCh. 9 - 9-25 to 9-28 The weldment shown in the figure is...Ch. 9 - 9-25 to 9-28 The weldment shown in the figure is...Ch. 9 - Prob. 27PCh. 9 - 925 to 928 The weldment shown in the figure is...Ch. 9 - The permissible shear stress for the weldment...Ch. 9 - Prob. 30PCh. 9 - 9-30 to 9-31 A steel bar of thickness h is...Ch. 9 - In the design of weldments in torsion it is...Ch. 9 - Prob. 33PCh. 9 - Prob. 34PCh. 9 - The attachment shown carries a static bending load...Ch. 9 - The attachment in Prob. 935 has not had its length...Ch. 9 - Prob. 37PCh. 9 - Prob. 39PCh. 9 - Prob. 40PCh. 9 - Prob. 42PCh. 9 - 9-43 to 9-45 A 2-in dia. steel bar is subjected to...Ch. 9 - 9-43 to 9-45 A 2-in dia. steel bar is subjected to...Ch. 9 - Prob. 45PCh. 9 - Prob. 46PCh. 9 - Find the maximum shear stress in the throat of the...Ch. 9 - The figure shows a welded steel bracket loaded by...Ch. 9 - Prob. 49PCh. 9 - Prob. 50PCh. 9 - Prob. 51PCh. 9 - Brackets, such as the one shown, are used in...Ch. 9 - For the sake of perspective it is always useful to...Ch. 9 - Hardware stores often sell plastic hooks that can...Ch. 9 - For a balanced double-lap joint cured at room...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- يكا - put 96** I need a detailed drawing with explanation or in wake, and the top edge of im below the free surface of the water. Determine the hydrothed if hydrostatic on the Plot the displacement diagram for a cam with roller follower of diameter 10 mm. The required motion is as follows; 1- Rising 60 mm in 135° with uniform acceleration and retardation motion. 2- Dwell 90° 3- Falling 60 mm for 135° with Uniform acceleration-retardation motion. Then design the cam profile to give the above displacement diagram if the minimum circle diameter of the cam is 50 mm. =--20125 7357 750 X 2.01arrow_forwardYou are working as an engineer in a bearing systems design company. The flow of lubricant inside a hydrodynamic bearing (µ = 0.001 kg m¯¹ s¯¹) can be approximated as a parallel, steady, two-dimensional, incompressible flow between two parallel plates. The top plate, representing the moving part of the bearing, travels at a constant speed, U, while the bottom plate remains stationary (Figure Q1). The plates are separated by a distance of 2h = 1 cm and are W = 20 cm wide. Their length is L = 10 cm. By applying the above approximations to the Navier-Stokes equations and assuming that end effects can be neglected, the horizontal velocity profile can be shown to be U y = +h У 2h = 1 cm 1 x1 y=-h u(y) = 1 dP 2μ dx -y² + Ay + B moving plate - U stationary plate 2 I2 L = 10 cm Figure Q1: Flow in a hydrodynamic bearing. The plates extend a width, W = 20 cm, into the page. (a) By considering the appropriate boundary conditions, show that the constants take the following forms: A = U 2h U 1 dP…arrow_forwardQuestion 2 You are an engineer working in the propulsion team for a supersonic civil transport aircraft driven by a turbojet engine, where you have oversight of the design for the engine intake and the exhaust nozzle, indicated in Figure Q2a. The turbojet engine can operate when provided with air flow in the Mach number range, 0.60 to 0.80. You are asked to analyse a condition where the aircraft is flying at 472 m/s at an altitude of 14,000 m. For all parts of the question, you can assume that the flow path of air through the engine has a circular cross section. (a) normal shock 472 m/s A B (b) intake engine altitude: 14,000 m D exhaust nozzle→ exit to atmosphere 472 m/s 50 m/s B diameter: DE = 0.30 m EX diameter: DF = 0.66 m Figure Q2: Propulsion system for a supersonic aircraft. F a) When the aircraft is at an altitude of 14,000 m, use the International Standard Atmosphere in the Module Data Book to state the local air pressure and tempera- ture. Thus show that the aircraft speed of…arrow_forward
- given below: A rectangular wing with wing twist yields the spanwise circulation distribution kbV1 roy) = kbv. (2) where k is a constant, b is the span length and V. is the free-stream velocity. The wing has an aspect ratio of 4. For all wing sections, the lift curve slope (ag) is 2 and the zero-lift angle of attack (a=0) is 0. a. Derive expressions for the downwash (w) and induced angle of attack a distributions along the span. b. Derive an expression for the induced drag coefficient. c. Calculate the span efficiency factor. d. Calculate the value of k if the wing has a washout and the difference between the geometric angles of attack of the root (y = 0) and the tip (y = tb/2) is: a(y = 0) a(y = ±b/2) = /18 Hint: Use the coordinate transformation y = cos (0)arrow_forward۳/۱ العنوان O не شكا +91x PU + 96852 A heavy car plunges into a lake during an accident and lands at the bottom of the lake on its wheels as shown in figure. The door is 1.2 m high and I m wide, and the top edge of Deine the hadrostatic force on the Plot the displacement diagram for a cam with roller follower of diameter 10 mm. The required motion is as follows; 1- Rising 60 mm in 135° with uniform acceleration and retardation motion. 2- Dwell 90° 3- Falling 60 mm for 135° with Uniform acceleration-retardation motion. Then design the cam profile to give the above displacement diagram if the minimum circle diameter of the cam is 50 mm. = -20125 750 x2.01arrow_forwardPlot the displacement diagram for a cam with roller follower of diameter 10 mm. The required motion is as follows; 1- Rising 60 mm in 135° with uniform acceleration and retardation motion. 2- Dwell 90° 3- Falling 60 mm for 135° with Uniform acceleration-retardation motion. Then design the cam profile to give the above displacement diagram if the minimum circle diameter of the cam is 50 mm.arrow_forward
- Q1/ A vertical, circular gate with water on one side as shown. Determine the total resultant force acting on the gate and the location of the center of pressure, use water specific weight 9.81 kN/m³ 1 m 4 marrow_forwardI need handwritten solution with sketches for eacharrow_forwardGiven answers to be: i) 14.65 kN; 6.16 kN; 8.46 kN ii) 8.63 kN; 9.88 kN iii) Bearing 6315 for B1 & B2, or Bearing 6215 for B1arrow_forward
- (b) A steel 'hot rolled structural hollow section' column of length 5.75 m, has the cross-section shown in Figure Q.5(b) and supports a load of 750 kN. During service, it is subjected to axial compression loading where one end of the column is effectively restrained in position and direction (fixed) and the other is effectively held in position but not in direction (pinned). i) Given that the steel has a design strength of 275 MN/m², determine the load factor for the structural member based upon the BS5950 design approach using Datasheet Q.5(b). [11] ii) Determine the axial load that can be supported by the column using the Rankine-Gordon formula, given that the yield strength of the material is 280 MN/m² and the constant *a* is 1/30000. [6] 300 600 2-300 mm wide x 5 mm thick plates. Figure Q.5(b) L=5.75m Pinned Fixedarrow_forwardHelp ارجو مساعدتي في حل هذا السؤالarrow_forwardHelp ارجو مساعدتي في حل هذا السؤالarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Differences between Temporary Joining and Permanent Joining.; Author: Academic Gain Tutorials;https://www.youtube.com/watch?v=PTr8QZhgXyg;License: Standard Youtube License