Concepts of Genetics (12th Edition)
Concepts of Genetics (12th Edition)
12th Edition
ISBN: 9780134604718
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino, Darrell Killian
Publisher: PEARSON
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Chapter 9, Problem 2NST

In aerobically cultured yeast, a petite mutant is isolated.

To determine the type of mutation causing this phenotype, the petite and wild-type strains are crossed. Such a cross has three potential outcomes.

  1. (a) all wild type
  2. (b) some petite, some wild type
  3. (c) all petite

For each set of results, what conclusion about the type of petite mutation is justified?

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DNK dagi nukleotidlar va undan sintezlangan oqsildagi peptid boglar farqi 901 taga teng bo'lib undagi A jami H boglardan 6,5 marta kam bo'lsa DNK dagi jami H bog‘lar sonini toping
One of the ways for a cell to generate ATP is through the oxidative phosphorylation. In oxidative phosphorylation 3 ATP are produced from every one NADH molecule. In respiration, every glucose molecule produces 10 NADH molecules. If a cell is growing on 5 glucose molecules, how much ATP can be produced using oxidative phosphorylation/aerobic respiration?
If a cell is growing on 5 glucose molecules, how much ATP can be produced using oxidative phosphorylation/aerobic respiration?

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Concepts of Genetics (12th Edition)

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Mitochondrial mutations; Author: Useful Genetics;https://www.youtube.com/watch?v=GvgXe-3RJeU;License: CC-BY