Concept explainers
(a) Using the superposition theorem, determine the current through the 12
b. Convert both voltage sources to current sources and recalculate the current to the 12
c. How do the results of parts (a) and (b) compare?
Fig. 9.125
(a)
The current through
Answer to Problem 1P
The current through
Explanation of Solution
Given:
The resistors values are
The voltage sources are
Concept Used:
Elements in the series have the same current.
Elements in the parallels have the same voltage.
Superposition theorem states that in any linear bilateral network having more than one source response in any one of the branches is equal to algebraic sum of the responses caused by individual source while rest of the sources are replaced by their internal impedances.
Short circuit the voltage source and open circuit the current source.
If the resistors are in series, then the value of the equivalent resistance for N series resistors is
If the resistors are in parallel, then the value of the equivalent resistance for N series resistors is
The special case for only two parallel resistors is
Current:
Current division is used to express the current across one of several parallel resistors in terms of current across the combination:
If there are two resistors in parallel then the current across second resistor is
Calculation:
Firstly, short circuit the voltage source
Conclusion:
Hence, the current through
(b)
The current through
Answer to Problem 1P
The current through
Explanation of Solution
Given:
The resistors values are
The voltage sources are
Concept Used:
Elements in the series have the same current.
Elements in the parallels have the same voltage.
Superposition theorem states that in any linear bilateral network having more than one source response in any one of the branches is equal to algebraic sum of the responses caused by individual source while rest of the sources are replaced by their internal impedances.
Short circuit the voltage source and open circuit the current source.
If the resistors are in series, then the value of the equivalent resistance for N series resistors is
If the resistors are in parallel, then the value of the equivalent resistance for N series resistors is
The special case for only two parallel resistors is
Current:
Current division is used to express the current across one of several parallel resistors in terms of current across the combination:
If there are two resistors in parallel then the current across second resistor is
Calculation:
Conclusion:
Hence, the current through
(c)
Compare the results of both the part (a) and (b).
Answer to Problem 1P
The results are similar in both the part (a) and (b).
Explanation of Solution
Given:
The resistors values are
The voltage sources are
Concept Used:
Elements in the series have the same current.
Elements in the parallels have the same voltage.
Superposition theorem states that in any linear bilateral network having more than one source response in any one of the branches is equal to algebraic sum of the responses caused by individual source while rest of the sources are replaced by their internal impedances.
Short circuit the voltage source and open circuit the current source.
Calculation:
The results are similar in both the part (a) and (b).
Conclusion:
Hence, the results are similar in both the part (a) and (b).
Want to see more full solutions like this?
Chapter 9 Solutions
Introductory Circuit Analysis (13th Edition)
Additional Engineering Textbook Solutions
Fundamentals of Applied Electromagnetics (7th Edition)
Electrical Engineering: Principles & Applications (7th Edition)
Applied Statics and Strength of Materials (6th Edition)
C++ How to Program (10th Edition)
Problem Solving with C++ (10th Edition)
Software Engineering (10th Edition)
- 4. Find the total equivalent Resistance (Rab). 652 212 12 barrow_forwardImplement the electrical circuit and transfer the obtained graph to the grid. Source with voltage of U = 12 V / 60Hz, R = 1 KQ. www.wwwmmmm www ww Resistor voltage with voltmeter: Calculate: UR IR URMS U peak U peak-peak G f UR R OSCarrow_forward1. Simulate the following circuit, use a DC source as V. Put a load of your choice at Vo terminals. Find the voltage Vo using voltage proves and find current in the branches of the circuit using current probes. Lastly perform a DC Sweep on the circuit and write your results. [4 marks] 10 µF H 36 V 27 ΚΩ 10 µF 150 ΚΩ 360 ΚΩ RF. RF 10µF 3302 50 μFarrow_forward
- Please show your detailed solution Number 19 How much power is represented by a circuit in which the voltage and current equations are e = 180 sin314t and i = 42 sin 314t? A. 771 W C. 7560 W B. 3780 W D. 5346 Warrow_forwardDept. of Electrical Engineering Fundamer EE1301 Dr. Naser Al-Falahy Practice Problem Find I in the circuit using the superposition principle 22 62 I 82 8 V 6 V 2 A Answer: 375 mAarrow_forwardSolve it quickly pleasearrow_forward
- Design and draw a series and parallel combination circuit comprising of oneseries resistor and two parallel branches, each having one resistor andrespective branch currents of: 1/3 mA and 2/3 mA, using a DC power supplyof 3V.arrow_forward10. Determine the reading (in ohms) of an ohmmeter for the given circuit at point: a.) AB b.) AC c.) BC Given Circuit: See attached imagearrow_forwardSolve the equivalent resistance across: a.) "a" and "b" b.) "b and "d"arrow_forward
- Electrical Engineering Determine the current Io using mesh analysis UTM UT j2 n StM UTM 5 UTM 420° UTM 25290° V mh UTM UTM UM 1520° A 2UTM UTSUTM UM - j4n TM I3 10Ω M UTM I4arrow_forwarda) By,carefully observing the circuit, Find the between co k S,4KSZ and resistors located on side of the circuit given 'in Figun equivalent resistance 12 KSZ the right hand b) Redraw the circuit with the equivalent resistance and the rest of the Cincuit. C) Applying Kirchoffs current Law to appropriate nodes find the current, lo d) using Kirchoffs Voltage Law find the Voltagé V. giren in Figun below Vxarrow_forwardPlease help me Determine and sketch the Vo for each of the network shown. Thank you very mucharrow_forward
- Delmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage Learning