UNDERSTANDING THE UNIVERSE(LL)-W/CODE
3rd Edition
ISBN: 9780393869903
Author: PALEN
Publisher: NORTON
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Chapter 9, Problem 14QAP
To determine
The statistical meaning of the given statement.
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The mass of an average comet's nucleus is about 1.0 ✕ 1014 kg. If the Oort cloud contains 2.0 ✕ 1011 comet nuclei, what is the mass of the cloud in units of Earth masses? (Note: Earth's mass is 5.97 ✕ 1024 kg.)________ m
____ days
There are two parts to this question. Thank you!
Chapter 9 Solutions
UNDERSTANDING THE UNIVERSE(LL)-W/CODE
Ch. 9.1 - Prob. 9.1CYUCh. 9.2 - Prob. 9.2CYUCh. 9.3 - Prob. 9.3CYUCh. 9.4 - Prob. 9.4CYUCh. 9.5 - Prob. 9.5CYUCh. 9.6 - Prob. 9.6CYUCh. 9 - Prob. 1QAPCh. 9 - Prob. 2QAPCh. 9 - Prob. 3QAPCh. 9 - Prob. 4QAP
Ch. 9 - Prob. 5QAPCh. 9 - Prob. 6QAPCh. 9 - Prob. 7QAPCh. 9 - Prob. 8QAPCh. 9 - Prob. 9QAPCh. 9 - Prob. 10QAPCh. 9 - Prob. 11QAPCh. 9 - Prob. 12QAPCh. 9 - Prob. 13QAPCh. 9 - Prob. 14QAPCh. 9 - Prob. 15QAPCh. 9 - Prob. 16QAPCh. 9 - Prob. 17QAPCh. 9 - Prob. 18QAPCh. 9 - Prob. 19QAPCh. 9 - Prob. 20QAPCh. 9 - Prob. 21QAPCh. 9 - Prob. 22QAPCh. 9 - Prob. 23QAPCh. 9 - Prob. 24QAPCh. 9 - Prob. 25QAPCh. 9 - Prob. 26QAPCh. 9 - Prob. 27QAPCh. 9 - Prob. 28QAPCh. 9 - Prob. 29QAPCh. 9 - Prob. 30QAPCh. 9 - Prob. 31QAPCh. 9 - Prob. 32QAPCh. 9 - Prob. 33QAPCh. 9 - Prob. 34QAPCh. 9 - Prob. 35QAPCh. 9 - Prob. 36QAPCh. 9 - Prob. 37QAPCh. 9 - Prob. 38QAPCh. 9 - Prob. 39QAPCh. 9 - Prob. 40QAPCh. 9 - Prob. 41QAPCh. 9 - Prob. 42QAPCh. 9 - Prob. 43QAPCh. 9 - Prob. 44QAPCh. 9 - Prob. 45QAP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- The mass of an average comet's nucleus is about 1.0 x 1014 kg. If the Oort cloud contains 2.0 x 101 comet nuclei, what is the mass of the cloud in units of Earth masses? (Note: Earth's mass is 5.97 x 1024 kg.) M. Compare that with Saturn's mass. (Note: Saturn's mass in units of Earth's mass is 95.2 M.) mass of the Oort cloud mass of Saturnarrow_forwardThere are two parts to this question. The answers are not 4.690117253 abd 0.2742758627. Please help!arrow_forwardA crater on the Moon is 28 km in diameter. If a typical meteorite is 11 times smaller than the diameter of the crater, what was the diameter (in km) of the original meteorite? km What is the estimated depth (in km) of the crater if its depth is one-ninth its diameter? kmarrow_forward
- Which meteorites are the most useful for defining the age of the solar system? Why?arrow_forward6arrow_forwardYou observe a comet 0.46 AU from Earth with a tail that is 1.7 degrees long. How long is the tail in AU? How long is the tail in kilometers? How many times could the U.S. fit along the length of the tail? (The width of the U.S. is 4,313 km.)arrow_forward
- Which of the following is least reasonable regarding comets? Group of answer choices Short-period comets originate in the Kuiper belt and take less than than about 200 years to orbit the Sun. Long-period comets originate in the Oort cloud and can take millions of years to orbit around the Sun, in randomly oriented orbital planes. The ion tail of a comet tends to produce a blue glow, as the ions inside it absorb sunlight and re-emit the absorbed energy with a characteristic color (somewhat like the gas atoms in a neon light or in an Aurora). An ion tail is typically narrow and straight and always trails the comet, like long hair in the wind. The dust tail of a comet often looks curved and its whitish color is just reflected sunlight.arrow_forward___ kmarrow_forwardIf the velocity of the Solar Wind about 4.0 x 10^2 km/s and the visible tail of a comet of 9.0 x 10^8 km long, how many days does an atom in the solar wind take to travel from the nucleus to the end of the visible tail? (note: 1 day= 86,400 sec) _______ daysarrow_forward
- The value we have just calculated is the combined masses of Jupiter and Callisto! Their mass is in units of the Sun's Mass (MS) - we can convert this to units which are more familiar to us like kilograms by multiplying this answer by the scale factor (1.99x1030 kg/1 MS): (MJupiter + MCallisto) = ( MS) (1.99x1030 kg/1 Solar Mass) = _______x_10___ kg (I have already written the x 10 so you are reminded to write the exponenet of 10 in the scientific notation expression of your answer). Since you know from looking at pictures of Jupiter with its Galilean Satellites (look in your book at a picture if you have not already), that Callisto is much smaller than Jupiter - in fact it is less than 0.001 of Jupiter's size or mass, so the number we have just calculated for (MJupiter + MCallisto) is almost the same as MJupiter . How much more massive is Jupiter than the Earth? (The mass of Earth is about 5.98 x 1024 kg)arrow_forwardGive me the solution for the problem. The correct answers are: A: -1.4 x 10-6 km/h. The comet's speed has been decreased by this amount. Hence, the effect is negligble. B: -6.7 x 10-8 km/h. The Earth's speed has been decreased by this amount. Also, the effect is negligble.arrow_forwardSuppose the average mass of each of 20,000 asteroids in the solar system is 1017 kg. Compare the total mass of these asteroids to the mass of Earth. Assuming a spherical shape and a density of 3000 kg/m3, estimate the diameter of an asteroid having this average mass.arrow_forward
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