The structures for the isomers A, B, and C of the compound with molecular formula, C 5 H 11 Br are to be interpreted from the given DEPT 13 C − NMR spectra. Concept introduction: DEPT stands for distortionless enhancement by polarization transfer. DEPT 13 C − NMR is used to indicate the number of hydrogen atoms that are bonded to each carbon while providing the information of chemical shift in a broadband proton-decoupled 13 C − NMR spectrum. The carbon signals in a DEPT spectrum are classified as CH 3 , CH 2 , CH or C accordingly. Presence of the electronegative compounds like halogens or oxygen or sulfur elements will downfield the signal, i.e., the chemical shift will occur at higher δ than the unsubstituted carbons.

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Answer 1

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Chapter 9, Problem 14PP

Interpretation Introduction

Interpretation:

The structures for the isomers A, B, and C of the compound with molecular formula, C₅H₁₁ Br are to be interpreted from the given DEPT 13C−NMR spectra.

Concept introduction:

DEPT stands for distortionless enhancement by polarization transfer. DEPT 13C−NMR is used to indicate the number of hydrogen atoms that are bonded to each carbon while providing the information of chemical shift in a broadband proton-decoupled 13C−NMR spectrum. The carbon signals in a DEPT spectrum are classified as CH3,CH2,CH or C accordingly.

Presence of the electronegative compounds like halogens or oxygen or sulfur elements will downfield the signal, i.e., the chemical shift will occur at higher δ than the unsubstituted carbons.

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Answer 2

Question

Chapter 9, Problem 14PP

Interpretation Introduction

Interpretation:

The structures for the isomers A, B, and C of the compound with molecular formula, C₅H₁₁ Br are to be interpreted from the given DEPT 13C−NMR spectra.

Concept introduction:

DEPT stands for distortionless enhancement by polarization transfer. DEPT 13C−NMR is used to indicate the number of hydrogen atoms that are bonded to each carbon while providing the information of chemical shift in a broadband proton-decoupled 13C−NMR spectrum. The carbon signals in a DEPT spectrum are classified as CH3,CH2,CH or C accordingly.

Presence of the electronegative compounds like halogens or oxygen or sulfur elements will downfield the signal, i.e., the chemical shift will occur at higher δ than the unsubstituted carbons.

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Answer 3

Question

Chapter 9, Problem 14PP

Interpretation Introduction

Interpretation:

The structures for the isomers A, B, and C of the compound with molecular formula, C₅H₁₁ Br are to be interpreted from the given DEPT 13C−NMR spectra.

Concept introduction:

DEPT stands for distortionless enhancement by polarization transfer. DEPT 13C−NMR is used to indicate the number of hydrogen atoms that are bonded to each carbon while providing the information of chemical shift in a broadband proton-decoupled 13C−NMR spectrum. The carbon signals in a DEPT spectrum are classified as CH3,CH2,CH or C accordingly.

Presence of the electronegative compounds like halogens or oxygen or sulfur elements will downfield the signal, i.e., the chemical shift will occur at higher δ than the unsubstituted carbons.

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Answer 4

Question

Chapter 9, Problem 14PP

Interpretation Introduction

Interpretation:

The structures for the isomers A, B, and C of the compound with molecular formula, C₅H₁₁ Br are to be interpreted from the given DEPT 13C−NMR spectra.

Concept introduction:

DEPT stands for distortionless enhancement by polarization transfer. DEPT 13C−NMR is used to indicate the number of hydrogen atoms that are bonded to each carbon while providing the information of chemical shift in a broadband proton-decoupled 13C−NMR spectrum. The carbon signals in a DEPT spectrum are classified as CH3,CH2,CH or C accordingly.

Presence of the electronegative compounds like halogens or oxygen or sulfur elements will downfield the signal, i.e., the chemical shift will occur at higher δ than the unsubstituted carbons.

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Answer 5

Chapter 9, Problem 14PP

Interpretation Introduction

Interpretation:

The structures for the isomers A, B, and C of the compound with molecular formula, C₅H₁₁ Br are to be interpreted from the given DEPT 13C−NMR spectra.

Concept introduction:

DEPT stands for distortionless enhancement by polarization transfer. DEPT 13C−NMR is used to indicate the number of hydrogen atoms that are bonded to each carbon while providing the information of chemical shift in a broadband proton-decoupled 13C−NMR spectrum. The carbon signals in a DEPT spectrum are classified as CH3,CH2,CH or C accordingly.

Presence of the electronegative compounds like halogens or oxygen or sulfur elements will downfield the signal, i.e., the chemical shift will occur at higher δ than the unsubstituted carbons.

Answer 6

Chapter 9, Problem 14PP

Interpretation Introduction

Interpretation:

The structures for the isomers A, B, and C of the compound with molecular formula, C₅H₁₁ Br are to be interpreted from the given DEPT 13C−NMR spectra.

Concept introduction:

DEPT stands for distortionless enhancement by polarization transfer. DEPT 13C−NMR is used to indicate the number of hydrogen atoms that are bonded to each carbon while providing the information of chemical shift in a broadband proton-decoupled 13C−NMR spectrum. The carbon signals in a DEPT spectrum are classified as CH3,CH2,CH or C accordingly.

Presence of the electronegative compounds like halogens or oxygen or sulfur elements will downfield the signal, i.e., the chemical shift will occur at higher δ than the unsubstituted carbons.

Answer 7

Chapter 9, Problem 14PP

Interpretation Introduction

Interpretation:

The structures for the isomers A, B, and C of the compound with molecular formula, C₅H₁₁ Br are to be interpreted from the given DEPT 13C−NMR spectra.

Concept introduction:

DEPT stands for distortionless enhancement by polarization transfer. DEPT 13C−NMR is used to indicate the number of hydrogen atoms that are bonded to each carbon while providing the information of chemical shift in a broadband proton-decoupled 13C−NMR spectrum. The carbon signals in a DEPT spectrum are classified as CH3,CH2,CH or C accordingly.

Presence of the electronegative compounds like halogens or oxygen or sulfur elements will downfield the signal, i.e., the chemical shift will occur at higher δ than the unsubstituted carbons.

Answer 8

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Answer 11

Ch. 9 - Prob. 1PP Ch. 9 - PRACTICE PROBLEM 9.2 What compound with molecular...Ch. 9 - PRACTICE PROBLEM 9.3 Using the method of Section...Ch. 9 - PRACTICE PROBLEM 9.4 How many signals would each...Ch. 9 - Prob. 5PP Ch. 9 - Prob. 6PP Ch. 9 - PRACTICE PROBLEM 9.7 The relative chemical shifts...Ch. 9 - Prob. 8PP Ch. 9 - PRACTICE PROBLEM 9.9 Propose a structure for...Ch. 9 - PRACTICE PROBLEM 9.10 What is the dihedral angle...

Solution Summary: The author explains that the structures for the isomers A, B, and C of the compound with molecular formula, C 5 H 11 Br are to be interpreted from the given DEPT 13

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