The order of the intermolecular forces and increasing boiling, melting points and enthalpy of vaporization are should be determined. Concept Introduction: Intermolecular forces: The forces involving within the molecule is called intermolecular forces thus, Ion-dipole forces: The attraction forces between anion charge end with opposite partial charge is called Ion-dipole forces. Dipole- Dipole forces: The attraction forces between ends of opposite partially charge in polar molecules is called Dipole- Dipole forces. Hydrogen bond: The weak bond between highly electronegative atom with partially positively charged Hydrogen is called Hydrogen bonding. London Dispersion Forces: The London dispersion force is the weaker force within the non polar molecules and which can be used to explain the state of the non polar molecules. The intermolecular forces are higher means the boiling point, melting points and enthalpy of vaporization of the compound is all so higher.

Question

Want to see the full answer?

Answer 1

Question

Chapter 9, Problem 136CP

Interpretation Introduction

Interpretation:

The order of the intermolecular forces and increasing boiling, melting points and enthalpy of vaporization are should be determined.

Concept Introduction:

Intermolecular forces:

The forces involving within the molecule is called intermolecular forces thus,

Ion-dipole forces:

         The attraction forces between anion charge end with opposite partial charge is called Ion-dipole forces.

Dipole- Dipole forces:

       The attraction forces between ends of opposite partially charge in polar molecules is called Dipole- Dipole forces.

Hydrogen bond:

         The weak bond between highly electronegative atom with partially positively charged Hydrogen is called Hydrogen bonding.

London Dispersion Forces:

         The London dispersion force is the weaker force within the non polar molecules and which can be used to explain the state of the non polar molecules.

The intermolecular forces are higher means the boiling point, melting points and enthalpy of vaporization of the compound is all so higher.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

MISSED THIS? Read Section 19.9 (Pages 878-881); Watch IWE 19.10 Consider the following reaction: CH3OH(g) CO(g) + 2H2(g) (Note that AG,CH3OH(g) = -162.3 kJ/mol and AG,co(g)=-137.2 kJ/mol.) Part A Calculate AG for this reaction at 25 °C under the following conditions: PCH₂OH Pco PH2 0.815 atm = 0.140 atm 0.170 atm Express your answer in kilojoules to three significant figures. Ο ΑΣΦ AG = -150 Submit Previous Answers Request Answer □? kJ × Incorrect; Try Again; 2 attempts remaining Calculate the free energy change under nonstandard conditions (AGrxn) by using the following relationship: AGrxn = AGrxn + RTInQ, AGxn+RTInQ, where AGxn is the standard free energy change, R is the ideal gas constant, T is the temperature in kelvins, a is the reaction quotient. Provide Feedback Next >

Identify and provide a brief explanation of Gas Chromatography (GC) within the context of chemical analysis of food. Incorporate the specific application name, provide a concise overview of sample preparation methods, outline instrumental parameters and conditions ultilized, and summarise the outcomes and findings achieved through this analytical approach.

Identify and provide a concise explanation of the concept of signal-to-noise ratio (SNR) in the context of chemical analysis. Provide specific examples.