Whetherthe normal melting point of substance X would be less than or greater than or equal to 225°C to be explained. Concept introduction Freezing point: Freezing point is defined as the temperature at which liquid into solid. Boiling point: Boiling point is temperature at which the liquid into gas. Elevation of boiling point: Elevation of boiling point of a liquid is occurrence that boiling point of a liquid would be greater when another substance is added to it. Resulting, the boiling point becomes higher than the pure solvent. Depression of freezing point: Depression of freezing point is reducing in freezing point of a solvent when added non volatile solute. Volatile substance means easily vaporized at room temperature and non volatile means does not easily evaporate at room temperature.

Question

Please help, this is all the calculations i got!!! I will rate!!!Approx mass of KMnO in vial: 3.464 4 Moss of beaker 3×~0. z Nax200: = 29.9219 Massof weacerv after remosimgain N2C2O4. Need to fill in all the missing blanks. ง ง Approx mass of KMnO4 in vials 3.464 Mass of beaker + 3x ~0-304: 29.9219 2~0.20 Miss of beaker + 2x- 29.7239 Mass of beaker + 1x~0.2g Naz (204 29-5249 Mass of beaver after removing as qa Na₂ C₂O T1 T2 T3 Final Buiet reading Initial butet reading (int)) Hass of NaOr used for Titration -reading (mL) calculation Results: 8.5ml 17mL 27.4mL Oml Om Oml T1 T2 T3 Moles of No CO Moles of KMO used LOF KM. O used Molenty of KMNO Averagem Of KMOWL

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Question

Chapter 9, Problem 107E

Interpretation Introduction

Interpretation: Whetherthe normal melting point of substance X would be less than or greater than or equal to 225°C to be explained.

Concept introduction

Freezing point: Freezing point is defined as the temperature at which liquid into solid.

Boiling point: Boiling point is temperature at which the liquid into gas.

Elevation of boiling point: Elevation of boiling point of a liquid is occurrence that boiling point of a liquid would be greater when another substance is added to it. Resulting, the boiling point becomes higher than the pure solvent.

Depression of freezing point: Depression of freezing point is reducing in freezing point of a solvent when added non volatile solute. Volatile substance means easily vaporized at room temperature and non volatile means does not easily evaporate at room temperature.

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Please help, this is all the calculations i got!!! I will rate!!!Approx mass of KMnO in vial: 3.464 4 Moss of beaker 3×~0. z Nax200: = 29.9219 Massof weacerv after remosimgain N2C2O4. Need to fill in all the missing blanks. ง ง Approx mass of KMnO4 in vials 3.464 Mass of beaker + 3x ~0-304: 29.9219 2~0.20 Miss of beaker + 2x- 29.7239 Mass of beaker + 1x~0.2g Naz (204 29-5249 Mass of beaver after removing as qa Na₂ C₂O T1 T2 T3 Final Buiet reading Initial butet reading (int)) Hass of NaOr used for Titration -reading (mL) calculation Results: 8.5ml 17mL 27.4mL Oml Om Oml T1 T2 T3 Moles of No CO Moles of KMO used LOF KM. O used Molenty of KMNO Averagem Of KMOWL

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