The molecular formula of the given compound is to be written. The hybridization of each carbon and oxygen atom is to be determined. The geometry of each carbon and oxygen atom is to be described. Concept introduction: Mixing of atomic orbitals to form degenerate molecular orbitals is called hybridization. Hybridization state of each atom is to be calculated from the total number of sigma bond pairs and lone pairs of that atom. If there are two electron domains on an atom, then the atom is s p hybridized. s p orbitals are formed by mixing of one s and one p . If there are three electron domains on an atom, then the atom is s p 2 hybridized. s p 2 orbitals are formed by mixing of one s and two p . If there are four electron domains on an atom, then the atom is s p 3 hybridized. s p 3 orbitals are formed by mixing of one s and three p . A single bond has a sigma bond. A double bond contains a sigma bond and a pi bond. A triple bond contains a sigma bond and two pi bonds.
The molecular formula of the given compound is to be written. The hybridization of each carbon and oxygen atom is to be determined. The geometry of each carbon and oxygen atom is to be described. Concept introduction: Mixing of atomic orbitals to form degenerate molecular orbitals is called hybridization. Hybridization state of each atom is to be calculated from the total number of sigma bond pairs and lone pairs of that atom. If there are two electron domains on an atom, then the atom is s p hybridized. s p orbitals are formed by mixing of one s and one p . If there are three electron domains on an atom, then the atom is s p 2 hybridized. s p 2 orbitals are formed by mixing of one s and two p . If there are four electron domains on an atom, then the atom is s p 3 hybridized. s p 3 orbitals are formed by mixing of one s and three p . A single bond has a sigma bond. A double bond contains a sigma bond and a pi bond. A triple bond contains a sigma bond and two pi bonds.
Solution Summary: The author explains the molecular formula of the given compound and the geometry of each carbon and oxygen atom.
Interpretation: The molecular formula of the given compound is to be written. The hybridization of each carbon and oxygen atom is to be determined. The geometry of each carbon and oxygen atom is to be described.
Concept introduction:
Mixing of atomic orbitals to form degenerate molecular orbitals is called hybridization.
Hybridization state of each atom is to be calculated from the total number of sigma bond pairs and lone pairs of that atom.
If there are two electron domains on an atom, then the atom is sp hybridized. sp orbitals are formed by mixing of one s and one p.
If there are three electron domains on an atom, then the atom is sp2 hybridized. sp2 orbitals are formed by mixing of one s and two p.
If there are four electron domains on an atom, then the atom is sp3 hybridized. sp3 orbitals are formed by mixing of one s and three p.
A single bond has a sigma bond.
A double bond contains a sigma bond and a pi bond.
A triple bond contains a sigma bond and two pi bonds.
Draw the products formed when the following alkene is treated with 03 followed by Zn, H₂O. Click the
"draw structure" button to launch the drawing utility.
draw structure ...
Calculate the pH of 0.600 M solution of CH5N (Kb=4.37 x10-4) Hint: use assumption and check it!
Draw all stereoisomers formed when the following alkene is treated with mCPBA. Be sure to answer all
parts.
Part 1:
How many stereoisomers of the product are possible?
1
Part 2 out of 2
Draw the product of the reaction, including stereochemistry.
edit structure ...
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Quantum Molecular Orbital Theory (PChem Lecture: LCAO and gerade ungerade orbitals); Author: Prof Melko;https://www.youtube.com/watch?v=l59CGEstSGU;License: Standard YouTube License, CC-BY