The molecular geometry of PBr 3 is to be determined. Concept introduction: In order to find the geometry of a molecule, follow the steps: First, draw the Lewis dot structure of the molecule. Find the number of electron pairs or domains around the central atom. Electron domain is the bond and lone pair of electrons around the central atom. Use the VSEPR model to find the electron domain geometry. According to VSEPR, the electron domains repel each other and arrange themselves as apart as possible in space. Molecular geometry is the arrangement of bonded atoms. If no lone pairs are present, the molecular geometry is the same as the electron domain geometry. The repulsion between two lone pairs is greater than that in case of lone pair–bond pair, which, in turn, is greater than the bond pair–bond pair repulsion.

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Answer 1

Question

Chapter 9, Problem 1KSP

Interpretation Introduction

Interpretation:

The molecular geometry of PBr3 is to be determined.

Concept introduction: In order to find the geometry of a molecule, follow the steps:

First, draw the Lewis dot structure of the molecule.

Find the number of electron pairs or domains around the central atom. Electron domain is the bond and lone pair of electrons around the central atom.

Use the VSEPR model to find the electron domain geometry.

According to VSEPR, the electron domains repel each other and arrange themselves as apart as possible in space.

Molecular geometry is the arrangement of bonded atoms. If no lone pairs are present, the molecular geometry is the same as the electron domain geometry.

The repulsion between two lone pairs is greater than that in case of lone pair–bond pair, which, in turn, is greater than the bond pair–bond pair repulsion.

Expert Solution & Answer

Answer to Problem 1KSP

Correct answer: Option (c)

Explanation of Solution

Reason for the correct option:

Lewis dot structure of PBr3 is shown below:

Chemistry, Chapter 9, Problem 1KSP

In this molecule, the phosphorus atom is bonded to three bromine atoms by single bonds and there is one lone pair on the phosphorus atom.

Thus, the electron domains around the phosphorus atom are four.

According to the VSEPR model, the four electron domains repel each other and arrange themselves in space in a tetrahedral shape.

However, in this case, one lone pair is present on the phosphorus atom.

Thus, the molecular geometry is trigonal pyramidal.

Hence, option (c) is correct.

Reasons for the incorrect options:

Option (a) is incorrect because a trigonal planar shape is obtained when there is no lone pair on the central atom.

Option (b) is incorrect because a tetrahedral shape is obtained when four bonds are present.

Option (d) is incorrect because a bent shape is obtained when there are two bonds present.

Option (e) is incorrect because a T-shape is obtained from the trigonal bipyramidal geometry with two lone pairs.

Hence, options (a), (b), (d), and (e) are incorrect.

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Students have asked these similar questions

1. Answer the questions about the following reaction: (a) Draw in the arrows that can be used make this reaction occur and draw in the product of substitution in this reaction. Be sure to include any relevant stereochemistry in the product structure. + SK F Br + (b) In which solvent would this reaction proceed the fastest (Circle one) Methanol Acetone (c) Imagine that you are working for a chemical company and it was your job to perform a similar reaction to the one above, with the exception of the S atom in this reaction being replaced by an O atom. During the reaction, you observe the formation of three separate molecules instead of the single molecule obtained above. What is the likeliest other products that are formed? Draw them in the box provided.

3. For the reactions below, draw the arrows corresponding to the transformations and draw in the boxes the reactants or products as indicated. Note: Part A should have arrows drawn going from the reactants to the middle structure and the arrows on the middle structure that would yield the final structure. For part B, you will need to draw in the reactant before being able to draw the arrows corresponding to product formation. A. B. Rearrangement ΘΗ

2. Draw the arrows required to make the following reactions occur. Please ensure your arrows point from exactly where you want to exactly where you want. If it is unclear from where arrows start or where they end, only partial credit will be given. Note: You may need to draw in lone pairs before drawing the arrows. A. B. H-Br 人 C Θ CI H Cl Θ + Br O

Answer 2

Question

Chapter 9, Problem 1KSP

Interpretation Introduction

Interpretation:

The molecular geometry of PBr3 is to be determined.

Concept introduction: In order to find the geometry of a molecule, follow the steps:

First, draw the Lewis dot structure of the molecule.

Find the number of electron pairs or domains around the central atom. Electron domain is the bond and lone pair of electrons around the central atom.

Use the VSEPR model to find the electron domain geometry.

According to VSEPR, the electron domains repel each other and arrange themselves as apart as possible in space.

Molecular geometry is the arrangement of bonded atoms. If no lone pairs are present, the molecular geometry is the same as the electron domain geometry.

The repulsion between two lone pairs is greater than that in case of lone pair–bond pair, which, in turn, is greater than the bond pair–bond pair repulsion.

Expert Solution & Answer

Answer to Problem 1KSP

Correct answer: Option (c)

Explanation of Solution

Reason for the correct option:

Lewis dot structure of PBr3 is shown below:

Chemistry, Chapter 9, Problem 1KSP

In this molecule, the phosphorus atom is bonded to three bromine atoms by single bonds and there is one lone pair on the phosphorus atom.

Thus, the electron domains around the phosphorus atom are four.

According to the VSEPR model, the four electron domains repel each other and arrange themselves in space in a tetrahedral shape.

However, in this case, one lone pair is present on the phosphorus atom.

Thus, the molecular geometry is trigonal pyramidal.

Hence, option (c) is correct.

Reasons for the incorrect options:

Option (a) is incorrect because a trigonal planar shape is obtained when there is no lone pair on the central atom.

Option (b) is incorrect because a tetrahedral shape is obtained when four bonds are present.

Option (d) is incorrect because a bent shape is obtained when there are two bonds present.

Option (e) is incorrect because a T-shape is obtained from the trigonal bipyramidal geometry with two lone pairs.

Hence, options (a), (b), (d), and (e) are incorrect.

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Answer 3

Question

Chapter 9, Problem 1KSP

Interpretation Introduction

Interpretation:

The molecular geometry of PBr3 is to be determined.

Concept introduction: In order to find the geometry of a molecule, follow the steps:

First, draw the Lewis dot structure of the molecule.

Find the number of electron pairs or domains around the central atom. Electron domain is the bond and lone pair of electrons around the central atom.

Use the VSEPR model to find the electron domain geometry.

According to VSEPR, the electron domains repel each other and arrange themselves as apart as possible in space.

Molecular geometry is the arrangement of bonded atoms. If no lone pairs are present, the molecular geometry is the same as the electron domain geometry.

The repulsion between two lone pairs is greater than that in case of lone pair–bond pair, which, in turn, is greater than the bond pair–bond pair repulsion.

Expert Solution & Answer

Answer to Problem 1KSP

Correct answer: Option (c)

Explanation of Solution

Reason for the correct option:

Lewis dot structure of PBr3 is shown below:

Chemistry, Chapter 9, Problem 1KSP

In this molecule, the phosphorus atom is bonded to three bromine atoms by single bonds and there is one lone pair on the phosphorus atom.

Thus, the electron domains around the phosphorus atom are four.

According to the VSEPR model, the four electron domains repel each other and arrange themselves in space in a tetrahedral shape.

However, in this case, one lone pair is present on the phosphorus atom.

Thus, the molecular geometry is trigonal pyramidal.

Hence, option (c) is correct.

Reasons for the incorrect options:

Option (a) is incorrect because a trigonal planar shape is obtained when there is no lone pair on the central atom.

Option (b) is incorrect because a tetrahedral shape is obtained when four bonds are present.

Option (d) is incorrect because a bent shape is obtained when there are two bonds present.

Option (e) is incorrect because a T-shape is obtained from the trigonal bipyramidal geometry with two lone pairs.

Hence, options (a), (b), (d), and (e) are incorrect.

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Answer 4

Question

Chapter 9, Problem 1KSP

Interpretation Introduction

Interpretation:

The molecular geometry of PBr3 is to be determined.

Concept introduction: In order to find the geometry of a molecule, follow the steps:

First, draw the Lewis dot structure of the molecule.

Find the number of electron pairs or domains around the central atom. Electron domain is the bond and lone pair of electrons around the central atom.

Use the VSEPR model to find the electron domain geometry.

According to VSEPR, the electron domains repel each other and arrange themselves as apart as possible in space.

Molecular geometry is the arrangement of bonded atoms. If no lone pairs are present, the molecular geometry is the same as the electron domain geometry.

The repulsion between two lone pairs is greater than that in case of lone pair–bond pair, which, in turn, is greater than the bond pair–bond pair repulsion.

Expert Solution & Answer

Answer to Problem 1KSP

Correct answer: Option (c)

Explanation of Solution

Reason for the correct option:

Lewis dot structure of PBr3 is shown below:

Chemistry, Chapter 9, Problem 1KSP

In this molecule, the phosphorus atom is bonded to three bromine atoms by single bonds and there is one lone pair on the phosphorus atom.

Thus, the electron domains around the phosphorus atom are four.

According to the VSEPR model, the four electron domains repel each other and arrange themselves in space in a tetrahedral shape.

However, in this case, one lone pair is present on the phosphorus atom.

Thus, the molecular geometry is trigonal pyramidal.

Hence, option (c) is correct.

Reasons for the incorrect options:

Option (a) is incorrect because a trigonal planar shape is obtained when there is no lone pair on the central atom.

Option (b) is incorrect because a tetrahedral shape is obtained when four bonds are present.

Option (d) is incorrect because a bent shape is obtained when there are two bonds present.

Option (e) is incorrect because a T-shape is obtained from the trigonal bipyramidal geometry with two lone pairs.

Hence, options (a), (b), (d), and (e) are incorrect.

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Answer 5

Chapter 9, Problem 1KSP

Interpretation Introduction

Interpretation:

The molecular geometry of PBr3 is to be determined.

Concept introduction: In order to find the geometry of a molecule, follow the steps:

First, draw the Lewis dot structure of the molecule.

Find the number of electron pairs or domains around the central atom. Electron domain is the bond and lone pair of electrons around the central atom.

Use the VSEPR model to find the electron domain geometry.

According to VSEPR, the electron domains repel each other and arrange themselves as apart as possible in space.

Molecular geometry is the arrangement of bonded atoms. If no lone pairs are present, the molecular geometry is the same as the electron domain geometry.

The repulsion between two lone pairs is greater than that in case of lone pair–bond pair, which, in turn, is greater than the bond pair–bond pair repulsion.

Expert Solution & Answer

Answer to Problem 1KSP

Correct answer: Option (c)

Explanation of Solution

Reason for the correct option:

Lewis dot structure of PBr3 is shown below:

Chemistry, Chapter 9, Problem 1KSP

In this molecule, the phosphorus atom is bonded to three bromine atoms by single bonds and there is one lone pair on the phosphorus atom.

Thus, the electron domains around the phosphorus atom are four.

According to the VSEPR model, the four electron domains repel each other and arrange themselves in space in a tetrahedral shape.

However, in this case, one lone pair is present on the phosphorus atom.

Thus, the molecular geometry is trigonal pyramidal.

Hence, option (c) is correct.

Reasons for the incorrect options:

Option (a) is incorrect because a trigonal planar shape is obtained when there is no lone pair on the central atom.

Option (b) is incorrect because a tetrahedral shape is obtained when four bonds are present.

Option (d) is incorrect because a bent shape is obtained when there are two bonds present.

Option (e) is incorrect because a T-shape is obtained from the trigonal bipyramidal geometry with two lone pairs.

Hence, options (a), (b), (d), and (e) are incorrect.

Answer 6

Chapter 9, Problem 1KSP

Interpretation Introduction

Interpretation:

The molecular geometry of PBr3 is to be determined.

Concept introduction: In order to find the geometry of a molecule, follow the steps:

First, draw the Lewis dot structure of the molecule.

Find the number of electron pairs or domains around the central atom. Electron domain is the bond and lone pair of electrons around the central atom.

Use the VSEPR model to find the electron domain geometry.

According to VSEPR, the electron domains repel each other and arrange themselves as apart as possible in space.

Molecular geometry is the arrangement of bonded atoms. If no lone pairs are present, the molecular geometry is the same as the electron domain geometry.

The repulsion between two lone pairs is greater than that in case of lone pair–bond pair, which, in turn, is greater than the bond pair–bond pair repulsion.

Expert Solution & Answer

Answer to Problem 1KSP

Correct answer: Option (c)

Explanation of Solution

Reason for the correct option:

Lewis dot structure of PBr3 is shown below:

Chemistry, Chapter 9, Problem 1KSP

In this molecule, the phosphorus atom is bonded to three bromine atoms by single bonds and there is one lone pair on the phosphorus atom.

Thus, the electron domains around the phosphorus atom are four.

According to the VSEPR model, the four electron domains repel each other and arrange themselves in space in a tetrahedral shape.

However, in this case, one lone pair is present on the phosphorus atom.

Thus, the molecular geometry is trigonal pyramidal.

Hence, option (c) is correct.

Reasons for the incorrect options:

Option (a) is incorrect because a trigonal planar shape is obtained when there is no lone pair on the central atom.

Option (b) is incorrect because a tetrahedral shape is obtained when four bonds are present.

Option (d) is incorrect because a bent shape is obtained when there are two bonds present.

Option (e) is incorrect because a T-shape is obtained from the trigonal bipyramidal geometry with two lone pairs.

Hence, options (a), (b), (d), and (e) are incorrect.

Answer 7

Chapter 9, Problem 1KSP

Interpretation Introduction

Interpretation:

The molecular geometry of PBr3 is to be determined.

Concept introduction: In order to find the geometry of a molecule, follow the steps:

First, draw the Lewis dot structure of the molecule.

Find the number of electron pairs or domains around the central atom. Electron domain is the bond and lone pair of electrons around the central atom.

Use the VSEPR model to find the electron domain geometry.

According to VSEPR, the electron domains repel each other and arrange themselves as apart as possible in space.

Molecular geometry is the arrangement of bonded atoms. If no lone pairs are present, the molecular geometry is the same as the electron domain geometry.

The repulsion between two lone pairs is greater than that in case of lone pair–bond pair, which, in turn, is greater than the bond pair–bond pair repulsion.

Answer 8

Expert Solution & Answer

Answer to Problem 1KSP

Correct answer: Option (c)

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Reason for the correct option:

Lewis dot structure of PBr3 is shown below:

Chemistry, Chapter 9, Problem 1KSP

In this molecule, the phosphorus atom is bonded to three bromine atoms by single bonds and there is one lone pair on the phosphorus atom.

Thus, the electron domains around the phosphorus atom are four.

According to the VSEPR model, the four electron domains repel each other and arrange themselves in space in a tetrahedral shape.

However, in this case, one lone pair is present on the phosphorus atom.

Thus, the molecular geometry is trigonal pyramidal.

Hence, option (c) is correct.

Reasons for the incorrect options:

Option (a) is incorrect because a trigonal planar shape is obtained when there is no lone pair on the central atom.

Option (b) is incorrect because a tetrahedral shape is obtained when four bonds are present.

Option (d) is incorrect because a bent shape is obtained when there are two bonds present.

Option (e) is incorrect because a T-shape is obtained from the trigonal bipyramidal geometry with two lone pairs.

Hence, options (a), (b), (d), and (e) are incorrect.

Answer 12

Ch. 9.1 - Practice Problem ATTEMPT Determine the shapes of...Ch. 9.1 - Prob. 1PPB Ch. 9.1 - Prob. 1PPC Ch. 9.1 - 9.1.1 What are the electron-domain geometry and...Ch. 9.1 - What are the electron-domain geometry and...Ch. 9.1 - Prob. 3CP Ch. 9.1 - Prob. 4CP Ch. 9.1 - Prob. 5CP Ch. 9.2 - Practice Problem ATTEMPT Ethanolamine has a...Ch. 9.2 - Practice Problem BUILD The bond angle in is...

Answer to Problem 1KSP

Explanation of Solution

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