a) Interpretation: The reaction given has a serious drawback. The potential problem in it is to be explained. Concept introduction: The addition of hydrogen halides to unsymmetrical alkenes occur following Markovnikov regiochemistry. The halogen adds to the more highly substituted carbon in the double bond while H adds to the less highly substituted carbon atom. To explain: The potential problem in the reaction given.

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Answer 1

Question

Chapter 8.SE, Problem 53AP

Interpretation Introduction

a)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

The addition of hydrogen halides to unsymmetrical alkenes occur following Markovnikov regiochemistry. The halogen adds to the more highly substituted carbon in the double bond while H adds to the less highly substituted carbon atom.

To explain:

The potential problem in the reaction given.

Interpretation Introduction

b)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

Alkenes undergo hydroxylation when treated first with O_sO₄ and then with NaHSO₃. The reaction occurs with syn stereochemistry. Both –OH groups add to the double bond from the same face to give a cis-1,2-diol as the product.

To explain:

The potential problem in the reaction given.

Interpretation Introduction

c)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

During ozonolysis ozone adds to the double bond in an alkene to give an ozonide. The ozonide on treatment with Zn in the presence of acid gets cleaved to yield carbonyl compounds as products. During the reaction each carbon in the double bond gets an oxygen atom.

To explain:

The potential problem in the reaction given.

Interpretation Introduction

d)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

Alkenes can be hydrated using hydroboration-oxidation reaction. The reaction occurs with syn stereochemistry following anti markovnokov regiochemistry. The addition of both H and OH takes place from the same face of the double bond. The boron and hence the –OH group gets attached to less highly substituted carbon.

To explain:

The potential problem in the reaction given.

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need help please and thanks dont understand only need help with C-F Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal…

Please correct answer and don't used hand raiting

need help please and thanks dont understand a-b Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal energy Divide the…

Answer 2

Question

Chapter 8.SE, Problem 53AP

Interpretation Introduction

a)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

The addition of hydrogen halides to unsymmetrical alkenes occur following Markovnikov regiochemistry. The halogen adds to the more highly substituted carbon in the double bond while H adds to the less highly substituted carbon atom.

To explain:

The potential problem in the reaction given.

Interpretation Introduction

b)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

Alkenes undergo hydroxylation when treated first with O_sO₄ and then with NaHSO₃. The reaction occurs with syn stereochemistry. Both –OH groups add to the double bond from the same face to give a cis-1,2-diol as the product.

To explain:

The potential problem in the reaction given.

Interpretation Introduction

c)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

During ozonolysis ozone adds to the double bond in an alkene to give an ozonide. The ozonide on treatment with Zn in the presence of acid gets cleaved to yield carbonyl compounds as products. During the reaction each carbon in the double bond gets an oxygen atom.

To explain:

The potential problem in the reaction given.

Interpretation Introduction

d)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

Alkenes can be hydrated using hydroboration-oxidation reaction. The reaction occurs with syn stereochemistry following anti markovnokov regiochemistry. The addition of both H and OH takes place from the same face of the double bond. The boron and hence the –OH group gets attached to less highly substituted carbon.

To explain:

The potential problem in the reaction given.

Expert Solution & Answer

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See solution

Answer 3

Question

Chapter 8.SE, Problem 53AP

Interpretation Introduction

a)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

The addition of hydrogen halides to unsymmetrical alkenes occur following Markovnikov regiochemistry. The halogen adds to the more highly substituted carbon in the double bond while H adds to the less highly substituted carbon atom.

To explain:

The potential problem in the reaction given.

Interpretation Introduction

b)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

Alkenes undergo hydroxylation when treated first with O_sO₄ and then with NaHSO₃. The reaction occurs with syn stereochemistry. Both –OH groups add to the double bond from the same face to give a cis-1,2-diol as the product.

To explain:

The potential problem in the reaction given.

Interpretation Introduction

c)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

During ozonolysis ozone adds to the double bond in an alkene to give an ozonide. The ozonide on treatment with Zn in the presence of acid gets cleaved to yield carbonyl compounds as products. During the reaction each carbon in the double bond gets an oxygen atom.

To explain:

The potential problem in the reaction given.

Interpretation Introduction

d)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

Alkenes can be hydrated using hydroboration-oxidation reaction. The reaction occurs with syn stereochemistry following anti markovnokov regiochemistry. The addition of both H and OH takes place from the same face of the double bond. The boron and hence the –OH group gets attached to less highly substituted carbon.

To explain:

The potential problem in the reaction given.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 8.SE, Problem 53AP

Interpretation Introduction

a)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

The addition of hydrogen halides to unsymmetrical alkenes occur following Markovnikov regiochemistry. The halogen adds to the more highly substituted carbon in the double bond while H adds to the less highly substituted carbon atom.

To explain:

The potential problem in the reaction given.

Interpretation Introduction

b)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

Alkenes undergo hydroxylation when treated first with O_sO₄ and then with NaHSO₃. The reaction occurs with syn stereochemistry. Both –OH groups add to the double bond from the same face to give a cis-1,2-diol as the product.

To explain:

The potential problem in the reaction given.

Interpretation Introduction

c)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

During ozonolysis ozone adds to the double bond in an alkene to give an ozonide. The ozonide on treatment with Zn in the presence of acid gets cleaved to yield carbonyl compounds as products. During the reaction each carbon in the double bond gets an oxygen atom.

To explain:

The potential problem in the reaction given.

Interpretation Introduction

d)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

Alkenes can be hydrated using hydroboration-oxidation reaction. The reaction occurs with syn stereochemistry following anti markovnokov regiochemistry. The addition of both H and OH takes place from the same face of the double bond. The boron and hence the –OH group gets attached to less highly substituted carbon.

To explain:

The potential problem in the reaction given.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 8.SE, Problem 53AP

Interpretation Introduction

a)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

The addition of hydrogen halides to unsymmetrical alkenes occur following Markovnikov regiochemistry. The halogen adds to the more highly substituted carbon in the double bond while H adds to the less highly substituted carbon atom.

To explain:

The potential problem in the reaction given.

Interpretation Introduction

b)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

Alkenes undergo hydroxylation when treated first with O_sO₄ and then with NaHSO₃. The reaction occurs with syn stereochemistry. Both –OH groups add to the double bond from the same face to give a cis-1,2-diol as the product.

To explain:

The potential problem in the reaction given.

Interpretation Introduction

c)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

During ozonolysis ozone adds to the double bond in an alkene to give an ozonide. The ozonide on treatment with Zn in the presence of acid gets cleaved to yield carbonyl compounds as products. During the reaction each carbon in the double bond gets an oxygen atom.

To explain:

The potential problem in the reaction given.

Interpretation Introduction

d)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

Alkenes can be hydrated using hydroboration-oxidation reaction. The reaction occurs with syn stereochemistry following anti markovnokov regiochemistry. The addition of both H and OH takes place from the same face of the double bond. The boron and hence the –OH group gets attached to less highly substituted carbon.

To explain:

The potential problem in the reaction given.

Answer 6

Chapter 8.SE, Problem 53AP

Interpretation Introduction

a)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

The addition of hydrogen halides to unsymmetrical alkenes occur following Markovnikov regiochemistry. The halogen adds to the more highly substituted carbon in the double bond while H adds to the less highly substituted carbon atom.

To explain:

The potential problem in the reaction given.

Answer 7

Chapter 8.SE, Problem 53AP

Interpretation Introduction

a)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

The addition of hydrogen halides to unsymmetrical alkenes occur following Markovnikov regiochemistry. The halogen adds to the more highly substituted carbon in the double bond while H adds to the less highly substituted carbon atom.

To explain:

The potential problem in the reaction given.

Answer 8

Interpretation Introduction

b)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

Alkenes undergo hydroxylation when treated first with O_sO₄ and then with NaHSO₃. The reaction occurs with syn stereochemistry. Both –OH groups add to the double bond from the same face to give a cis-1,2-diol as the product.

To explain:

The potential problem in the reaction given.

Answer 9

Interpretation Introduction

b)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

Alkenes undergo hydroxylation when treated first with O_sO₄ and then with NaHSO₃. The reaction occurs with syn stereochemistry. Both –OH groups add to the double bond from the same face to give a cis-1,2-diol as the product.

To explain:

The potential problem in the reaction given.

Answer 10

Interpretation Introduction

c)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

During ozonolysis ozone adds to the double bond in an alkene to give an ozonide. The ozonide on treatment with Zn in the presence of acid gets cleaved to yield carbonyl compounds as products. During the reaction each carbon in the double bond gets an oxygen atom.

To explain:

The potential problem in the reaction given.

Answer 11

Interpretation Introduction

c)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

During ozonolysis ozone adds to the double bond in an alkene to give an ozonide. The ozonide on treatment with Zn in the presence of acid gets cleaved to yield carbonyl compounds as products. During the reaction each carbon in the double bond gets an oxygen atom.

To explain:

The potential problem in the reaction given.

Answer 12

Interpretation Introduction

d)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

Alkenes can be hydrated using hydroboration-oxidation reaction. The reaction occurs with syn stereochemistry following anti markovnokov regiochemistry. The addition of both H and OH takes place from the same face of the double bond. The boron and hence the –OH group gets attached to less highly substituted carbon.

To explain:

The potential problem in the reaction given.

Answer 13

Interpretation Introduction

d)

Interpretation:

The reaction given has a serious drawback. The potential problem in it is to be explained.

Concept introduction:

Alkenes can be hydrated using hydroboration-oxidation reaction. The reaction occurs with syn stereochemistry following anti markovnokov regiochemistry. The addition of both H and OH takes place from the same face of the double bond. The boron and hence the –OH group gets attached to less highly substituted carbon.

To explain:

The potential problem in the reaction given.

Answer 14

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Answer 15

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Answer 16

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Answer 17

Ch. 8.1 - Prob. 1P Ch. 8.1 - How many alkene products, including E,Z isomers,...Ch. 8.2 - Prob. 3P Ch. 8.2 - Addition of HCl to 1, 2-dimethylcyclohexene yields...Ch. 8.3 - Prob. 5P Ch. 8.3 - Prob. 6P Ch. 8.4 - Prob. 7P Ch. 8.4 - From what alkenes might the following alcohols...Ch. 8.5 - Prob. 9P Ch. 8.5 - What alkenes might be used to prepare the...

Solution Summary: The author explains that the addition of hydrogen halides to unsymmetrical alkenes is not as per the Markovnikov regiochemistry.

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Chapter 8 Solutions