a) Interpretation: The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given. Concept introduction: The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on the halogen. In the second step water attacks the halonium ion from the least shielded side, followed by the loss of a proton to give an anti addition product. The addition to unsymmetrical alkenes follows Markovnikov regiochemistry. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents. To give: The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

Question

Hi!! Please provide a solution that is handwritten. Ensure all figures, reaction mechanisms (with arrows and lone pairs please!!), and structures are clearly drawn to illustrate the synthesis of the product as per the standards of a third year organic chemistry course. ****the solution must include all steps, mechanisms, and intermediate structures as required. Please hand-draw the mechanisms and structures to support your explanation. Don’t give me AI-generated diagrams or text-based explanations, no wordy explanations on how to draw the structures I need help with the exact mechanism hand drawn by you!!! I am reposting this—ensure all parts of the question are straightforward and clear or please let another expert handle it thanks!!

Answer 1

Question

Chapter 8.SE, Problem 27MP

Interpretation Introduction

a)

Interpretation:

The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given.

Concept introduction:

The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on the halogen. In the second step water attacks the halonium ion from the least shielded side, followed by the loss of a proton to give an anti addition product. The addition to unsymmetrical alkenes follows Markovnikov regiochemistry. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents.

To give:

The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

Interpretation Introduction

b)

Interpretation:

The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given.

Concept introduction:

The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX, to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on the halogen. In the second step water attacks the halonium ion from the least shielded side to give an anti addition product. The addition obeys Markovnikov orientation. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents.

To give:

The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

Interpretation Introduction

c)

Interpretation:

The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given.

Concept introduction:

The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX, to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on halogen. In the second step water attacks the halonium ion from the least shielded side to give an anti addition product. The addition obeys Markovnokov orientation. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents.

To give:

The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

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Hi!! Please provide a solution that is handwritten. Ensure all figures, reaction mechanisms (with arrows and lone pairs please!!), and structures are clearly drawn to illustrate the synthesis of the product as per the standards of a third year organic chemistry course. ****the solution must include all steps, mechanisms, and intermediate structures as required. Please hand-draw the mechanisms and structures to support your explanation. Don’t give me AI-generated diagrams or text-based explanations, no wordy explanations on how to draw the structures I need help with the exact mechanism hand drawn by you!!! I am reposting this—ensure all parts of the question are straightforward and clear or please let another expert handle it thanks!!

. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. < cleavage Bond A • CH3 + 26. t cleavage 2°C• +3°C• Bond C Cleavage CH3 ZC '2°C. 26. E Strongest 3°C. 2C. Gund Largest BDE weakest bond In that molecule a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. Weakest C bond Produces A Weakest Bond Most Strongest Bond Stable radical Strongest Gund produces least stable radicals b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 人 8°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. methyl radical •CH3 formed in bund A Cleavage

Which carbocation is more stable?

Answer 2

Question

Chapter 8.SE, Problem 27MP

Interpretation Introduction

a)

Interpretation:

The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given.

Concept introduction:

The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on the halogen. In the second step water attacks the halonium ion from the least shielded side, followed by the loss of a proton to give an anti addition product. The addition to unsymmetrical alkenes follows Markovnikov regiochemistry. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents.

To give:

The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

Interpretation Introduction

b)

Interpretation:

The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given.

Concept introduction:

The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX, to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on the halogen. In the second step water attacks the halonium ion from the least shielded side to give an anti addition product. The addition obeys Markovnikov orientation. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents.

To give:

The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

Interpretation Introduction

c)

Interpretation:

The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given.

Concept introduction:

The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX, to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on halogen. In the second step water attacks the halonium ion from the least shielded side to give an anti addition product. The addition obeys Markovnokov orientation. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents.

To give:

The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

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Answer 3

Question

Chapter 8.SE, Problem 27MP

Interpretation Introduction

a)

Interpretation:

The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given.

Concept introduction:

The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on the halogen. In the second step water attacks the halonium ion from the least shielded side, followed by the loss of a proton to give an anti addition product. The addition to unsymmetrical alkenes follows Markovnikov regiochemistry. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents.

To give:

The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

Interpretation Introduction

b)

Interpretation:

The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given.

Concept introduction:

The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX, to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on the halogen. In the second step water attacks the halonium ion from the least shielded side to give an anti addition product. The addition obeys Markovnikov orientation. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents.

To give:

The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

Interpretation Introduction

c)

Interpretation:

The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given.

Concept introduction:

The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX, to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on halogen. In the second step water attacks the halonium ion from the least shielded side to give an anti addition product. The addition obeys Markovnokov orientation. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents.

To give:

The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

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Answer 4

Question

Chapter 8.SE, Problem 27MP

Interpretation Introduction

a)

Interpretation:

The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given.

Concept introduction:

The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on the halogen. In the second step water attacks the halonium ion from the least shielded side, followed by the loss of a proton to give an anti addition product. The addition to unsymmetrical alkenes follows Markovnikov regiochemistry. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents.

To give:

The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

Interpretation Introduction

b)

Interpretation:

The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given.

Concept introduction:

The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX, to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on the halogen. In the second step water attacks the halonium ion from the least shielded side to give an anti addition product. The addition obeys Markovnikov orientation. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents.

To give:

The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

Interpretation Introduction

c)

Interpretation:

The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given.

Concept introduction:

The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX, to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on halogen. In the second step water attacks the halonium ion from the least shielded side to give an anti addition product. The addition obeys Markovnokov orientation. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents.

To give:

The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

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Answer 5

Chapter 8.SE, Problem 27MP

Interpretation Introduction

a)

Interpretation:

The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given.

Concept introduction:

The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on the halogen. In the second step water attacks the halonium ion from the least shielded side, followed by the loss of a proton to give an anti addition product. The addition to unsymmetrical alkenes follows Markovnikov regiochemistry. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents.

To give:

The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

Interpretation Introduction

b)

Interpretation:

The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given.

Concept introduction:

The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX, to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on the halogen. In the second step water attacks the halonium ion from the least shielded side to give an anti addition product. The addition obeys Markovnikov orientation. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents.

To give:

The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

Interpretation Introduction

c)

Interpretation:

The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given.

Concept introduction:

The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX, to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on halogen. In the second step water attacks the halonium ion from the least shielded side to give an anti addition product. The addition obeys Markovnokov orientation. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents.

To give:

The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

Answer 6

Chapter 8.SE, Problem 27MP

Interpretation Introduction

a)

Interpretation:

The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given.

Concept introduction:

The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on the halogen. In the second step water attacks the halonium ion from the least shielded side, followed by the loss of a proton to give an anti addition product. The addition to unsymmetrical alkenes follows Markovnikov regiochemistry. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents.

To give:

The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

Answer 7

Chapter 8.SE, Problem 27MP

Interpretation Introduction

a)

Interpretation:

The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given.

Concept introduction:

The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on the halogen. In the second step water attacks the halonium ion from the least shielded side, followed by the loss of a proton to give an anti addition product. The addition to unsymmetrical alkenes follows Markovnikov regiochemistry. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents.

To give:

The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

Answer 8

Interpretation Introduction

b)

Interpretation:

The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given.

Concept introduction:

The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX, to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on the halogen. In the second step water attacks the halonium ion from the least shielded side to give an anti addition product. The addition obeys Markovnikov orientation. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents.

To give:

The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

Answer 9

Interpretation Introduction

b)

Interpretation:

The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given.

Concept introduction:

The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX, to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on the halogen. In the second step water attacks the halonium ion from the least shielded side to give an anti addition product. The addition obeys Markovnikov orientation. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents.

To give:

The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

Answer 10

Interpretation Introduction

c)

Interpretation:

The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given.

Concept introduction:

The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX, to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on halogen. In the second step water attacks the halonium ion from the least shielded side to give an anti addition product. The addition obeys Markovnokov orientation. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents.

To give:

The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

Answer 11

Interpretation Introduction

c)

Interpretation:

The product of the reaction shown if the reaction was conducted in DMSO with water is to be given. The complete mechanism of the reaction including appropriate regiochemistry and stereochemistry is also to be given.

Concept introduction:

The addition of halogens to alkenes in the presence of aqueous DMSO results in the anti addition of the halohydrin, HOX, to the double bond. In the first step a cyclic halonium ion is formed by the attack of the double bond on halogen. In the second step water attacks the halonium ion from the least shielded side to give an anti addition product. The addition obeys Markovnokov orientation. The negative part (OH) adds to the doubly bonded carbon atom which has more number of substituents.

To give:

The product of the reaction shown if the reaction was conducted in DMSO with water and to give the complete mechanism of the reaction including appropriate regiochemistry and stereochemistry.

Answer 12

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Answer 23

Ch. 8.1 - Prob. 1P Ch. 8.1 - How many alkene products, including E,Z isomers,...Ch. 8.2 - Prob. 3P Ch. 8.2 - Addition of HCl to 1, 2-dimethylcyclohexene yields...Ch. 8.3 - Prob. 5P Ch. 8.3 - Prob. 6P Ch. 8.4 - Prob. 7P Ch. 8.4 - From what alkenes might the following alcohols...Ch. 8.5 - Prob. 9P Ch. 8.5 - What alkenes might be used to prepare the...

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