Explanation Express the wasted work potential during the throttling process. X destroyed = w r e v , o u t − w a c t , o u t X destroyed = T 0 S gen − 0 X destroyed = T 0 S gen (I) Here, surrounding temperature is T 0 and entropy generation is S gen . Express entropy generation by using an entropy balance on the device which is an adiabatic steady-flow system. S ˙ in − S ˙ out + S ˙ gen = Δ S ˙ system m ˙ s 1 − m ˙ s 2 + S ˙ gen = 0 S ˙ gen = m ˙ ( s 2 − s 1 ) s gen = s 2 − s 1 (II) Here, rate of net entropy transfer by heat and mass is S ˙ in − S ˙ out , rate of entropy generation is S ˙ gen , rate of change in entropy of system is Δ S ˙ system , initial and final specific entropy is s 1 and s 2 respectively, and rate of mass flow is m ˙ . Conclusion: Refer Table A-13, “superheated refrigerant-134a” and write the properties corresponding to initial pressure ( P 1 ) and initial temperature ( T 1 ) of 1 MPa and 100 ° C respectively. h 1 = 335.08 kJ / kg s 1 = 1.1032 kJ / kg ⋅ K Here, initial specific enthalpy is h 1 . Let the initial enthalpy and final enthalpy be same. h 1 = h 2 = 335.08 kJ / kg Here, final specific enthalpy is h 2 . Refer Table A-13, “superheated refrigerant” and write the properties corresponding to final pressure ( P 2 ) and final specific enthalpy of 0 .8 MPa and 335.08 kJ / kg respectively by using the interpolation method. Write the formula of interpolation method of two variables. y 2 = ( x 2 − x 1 ) ( y 3 − y 1 ) ( x 3 − x 1 ) + y 1 (III) Here, the variables denote by x and y is specific enthalpy and specific entropy respectively. Show the specific entropy at 3178 .3 kJ / kg and 3302 .9 kJ / kg as in Table (1). Final specific enthalpy h 2 ( kJ / kg ) Final specific entropy s 2 ( kJ / kg ⋅ K ) 337

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Author: CENGEL

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