Chapter 8.7, Problem 28PPE

To determine

To factor the expression $k^2-64$ .

Answer to Problem 28PPE

  $k^2-64=\left(k-8\right)\left(k+8\right)$

Explanation of Solution

Given:

  $k^2-64$

Concept used:

  $\left(a+b\right)\left(a-b\right)=a^2-b^2$

Calculation:

  $\begin{array}{l}{k}^2-64=k^2-8^2\\ =\left(k-8\right)\left(k+8\right)\end{array}$