Chapter 8, Problem 69CR

To determine

To factor the expression $32v^2-8$ .

Answer to Problem 69CR

  $32v^2-8=8\left(2v-1\right)\left(2v+1\right)$

Explanation of Solution

Given:

  $32v^2-8$

Concept used:

  $a^2-b^2=\left(a+b\right)\left(a-b\right)$

Calculation:

  $\begin{array}{l}32v^2-8=8\left(4v^2-1\right)\\ =8\left[{\left(2v\right)}^2-1^2\right]\\ =8\left(2v-1\right)\left(2v+1\right)\end{array}$