Chapter 8.3, Problem 4LC

To determine

To find the area of the rectangle, if it has length $x+5$ and width $x-3.$

Answer to Problem 4LC

The area of the rectangle is $x^2+2x-15$ .

Explanation of Solution

Given information:

Given rectangle has length $x+5$ and width $x-3.$

As we know that area of a rectangle is $\text{length}\times \text{width}$

  $\begin{array}{l}=\left(x+5\right)\left(x-3\right)\\ =x^2-3x+5x-15\\ =x^2+2x-15\end{array}$

Hence, the area of the rectangle is $x^2+2x-15$ .