Chapter 8.5, Problem 18E

To determine

To find: the angle of inclination of block with the horizontal.

Answer to Problem 18E

  $44°$

Explanation of Solution

Given information:

Weight of block = 75 pounds

Exerted force = 52.1 pound

Calculation:

The sketch for the given situation is as follows:

  

The given force has the same magnitude as the downhill component of weight. The angle of inclination with the horizontal can be evaluated as shown below.

  $\begin{array}{c}\overrightarrow{F}=\omega \sin \theta \\ 52.1=75\sin \theta \\ \sin \theta =\frac{52.1}{75}\\ \theta ={\sin }^{-1}\left(\frac{52.1}{75}\right)\\ \text{=}44°\end{array}$

Thus the angle of inclination is $44°$ .