Chapter 8, Problem 15SGA

To determine

To find: the magnitude and direction of the $3\overrightarrow{p}-\overrightarrow{q}$ resultant vector.

Answer to Problem 15SGA

  $\begin{array}{l}\text{Magnitude}=3.6\text{ cm}\\ \text{Direction}=95°\end{array}$

Explanation of Solution

Given information:

The vectors are as follows:

  

  $\begin{array}{l}\text{Magnitude of }\overrightarrow{p}=1.3\text{ cm}\\ \text{Direction of }\overrightarrow{p}=50°\\ \text{Magnitude of }\overrightarrow{q}=2.9\text{ cm}\\ \text{Direction of }\overrightarrow{q}=10°\end{array}$

Calculation:

The resultant diagram of $3\overrightarrow{p}-\overrightarrow{q}$ vector is as follows:

  

The length measure from tail to under the arrow head of the resultant is 3.6 cm. The direction of the vector is given by the angle measure and it is found to be $95°$ .