(a)
Interpretation:
The equation for the formation of ions of
Concept introduction:
The electronic configuration of an element tells about the distribution of electrons in the atomic orbitals. The electronic configuration is used to predict the physical, chemical, electrical and magnetic properties of the substance.
The condensed electronic configuration is a short way to write the electron distribution in terms of the nearest noble gas.
The electrons are filled up in accordance with three rules:
1. Aufbau principle which states that the electrons are filled up in the increasing order of their orbitals which follows as:
2. Hund’s rule which states that the pairing of electrons will not start until each of the orbitals is singly occupied.
3. Pauli’s exclusion principle states that no two electrons can have the same value of all the four quantum numbers.
(b)
Interpretation:
The equation for the formation of ions of
Concept introduction:
The electronic configuration of an element tells about the distribution of electrons in the atomic orbitals. The electronic configuration is used to predict the physical, chemical, electrical and magnetic properties of the substance.
The condensed electronic configuration is a short way to write the electron distribution in terms of the nearest noble gas.
The electrons are filled up in accordance with three rules:
1. Aufbau principle which states that the electrons are filled up in the increasing order of their orbitals which follows as:
2. Hund’s rule which states that the pairing of electrons will not start until each of the orbitals is singly occupied.
3. Pauli’s exclusion principle states that no two electrons can have the same value of all the four quantum numbers.
(c)
Interpretation:
The equation for the formation of ions of
Concept introduction:
The electronic configuration of an element tells about the distribution of electrons in the atomic orbitals. The electronic configuration is used to predict the physical, chemical, electrical and magnetic properties of the substance.
The condensed electronic configuration is a short way to write the electron distribution in terms of the nearest noble gas.
The electrons are filled up in accordance with three rules:
1. Aufbau principle which states that the electrons are filled up in the increasing order of their orbitals which follows as:
2. Hund’s rule which states that the pairing of electrons will not start until each of the orbitals is singly occupied.
3. Pauli’s exclusion principle states that no two electrons can have the same value of all the four quantum numbers.
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Chapter 8 Solutions
Chemistry The Molecular Nature Of Matter And Change 9th
- Diels Alder Cycloaddition: Focus on regiochemistry (problems E-F) –> match + of thedienophile and - of the diene while also considering stereochemistry (endo).arrow_forwardHELP! URGENT! PLEASE RESOND ASAP!arrow_forwardQuestion 4 Determine the rate order and rate constant for sucrose hydrolysis. Time (hours) [C6H12O6] 0 0.501 0.500 0.451 1.00 0.404 1.50 0.363 3.00 0.267 First-order, k = 0.210 hour 1 First-order, k = 0.0912 hour 1 O Second-order, k = 0.590 M1 hour 1 O Zero-order, k = 0.0770 M/hour O Zero-order, k = 0.4896 M/hour O Second-order, k = 1.93 M-1-hour 1 10 ptsarrow_forward
- Determine the rate order and rate constant for sucrose hydrolysis. Time (hours) [C6H12O6] 0 0.501 0.500 0.451 1.00 0.404 1.50 0.363 3.00 0.267arrow_forwardDraw the products of the reaction shown below. Use wedge and dash bonds to indicate stereochemistry. Ignore inorganic byproducts. OSO4 (cat) (CH3)3COOH Select to Draw ઘarrow_forwardCalculate the reaction rate for selenious acid, H2SeO3, if 0.1150 M I-1 decreases to 0.0770 M in 12.0 minutes. H2SeO3(aq) + 6I-1(aq) + 4H+1(aq) ⟶ Se(s) + 2I3-1(aq) + 3H2O(l)arrow_forward
- Problem 5-31 Which of the following objects are chiral? (a) A basketball (d) A golf club (b) A fork (c) A wine glass (e) A spiral staircase (f) A snowflake Problem 5-32 Which of the following compounds are chiral? Draw them, and label the chirality centers. (a) 2,4-Dimethylheptane (b) 5-Ethyl-3,3-dimethylheptane (c) cis-1,4-Dichlorocyclohexane Problem 5-33 Draw chiral molecules that meet the following descriptions: (a) A chloroalkane, C5H11Cl (c) An alkene, C6H12 (b) An alcohol, C6H140 (d) An alkane, C8H18 Problem 5-36 Erythronolide B is the biological precursor of erythromycin, a broad-spectrum antibiotic. How H3C CH3 many chirality centers does erythronolide B have? OH Identify them. H3C -CH3 OH Erythronolide B H3C. H3C. OH OH CH3arrow_forwardPLEASE HELP! URGENT! PLEASE RESPOND!arrow_forward2. Propose a mechanism for this reaction. ہلی سے ملی N H (excess)arrow_forward
- Steps and explanationn please.arrow_forwardProblem 5-48 Assign R or S configurations to the chirality centers in ascorbic acid (vitamin C). OH H OH HO CH2OH Ascorbic acid O H Problem 5-49 Assign R or S stereochemistry to the chirality centers in the following Newman projections: H Cl H CH3 H3C. OH H3C (a) H H H3C (b) CH3 H Problem 5-52 Draw the meso form of each of the following molecules, and indicate the plane of symmetry in each: OH OH (a) CH3CHCH2CH2CHCH3 CH3 H3C. -OH (c) H3C CH3 (b) Problem 5-66 Assign R or S configurations to the chiral centers in cephalexin, trade-named Keflex, the most widely prescribed antibiotic in the United States. H2N H IHH S Cephalexin N. CH3 CO₂Harrow_forwardSteps and explanationn please.arrow_forward
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