Parallel arrays: Arrays are used to group related data types together. The elements in two arrays with different variables that are related to their position are known as parallel arrays. Establishing relationship between two parallel arrays: Consider two arrays named “strMonth []” and “intBonus []” arrays are declared as follows: string strMonth[] = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"}; int intBonus[] = {25000, 26000, 27000, 29000, 31000, 34000, 36000, 37000, 38000, 40000, 41000, 45000}; Based on the above example, the relationship is established by using the same subscript for both the arrays. “strMonth[index]” have relationship on “intBonus[index]”. That is, the bonus amount of January month is 25000, February month is 26000, and so on.

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(1 point) By dragging statements from the left column to the right column below, give a proof by induction of the following statement: an = = 9" - 1 is a solution to the recurrence relation an = 9an-18 with ao = : 0. The correct proof will use 8 of the statements below. Statements to choose from: Note that a₁ = 9a0 + 8. Now assume that P(n) is true for all n ≥ 0. Your Proof: Put chosen statements in order in this column and press the Submit Answers button. Let P(n) be the predicate, "a = 9″ – 1". απ = 90 − 1 = Note that Let P(n) be the predicate, "an 9" - 1 is a solution to the recurrence relation an = 9an-1 +8 with ao = 0." - Now assume that P(k + 1) is true. Thus P(k) is true for all k. Thus P(k+1) is true. Then ak+1 = 9ak +8, so P(k + 1) is true. = 1 − 1 = 0, as required. Then = 9k — 1. ak Now assume that P(k) is true for an arbitrary integer k ≥ 1. By the recurrence relation, we have ak+1 = ak+1 = = 9ak + 8 = 9(9k − 1) + 8 This simplifies to 9k+19+8 = 9k+1 − 1 Then 9k+1 − 1 = 9(9*…

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Chapter 8.4, Problem 8.21CP

Program Plan Intro

Parallel arrays:

Arrays are used to group related data types together. The elements in two arrays with different variables that are related to their position are known as parallel arrays.

Establishing relationship between two parallel arrays:

Consider two arrays named “strMonth []” and “intBonus []” arrays are declared as follows:

string strMonth[] = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};

int intBonus[] = {25000, 26000, 27000, 29000, 31000, 34000, 36000, 37000, 38000, 40000, 41000, 45000};

Based on the above example, the relationship is established by using the same subscript for both the arrays. “strMonth[index]” have relationship on “intBonus[index]”. That is, the bonus amount of January month is 25000, February month is 26000, and so on.

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(1 point) By dragging statements from the left column to the right column below, give a proof by induction of the following statement: an = = 9" - 1 is a solution to the recurrence relation an = 9an-18 with ao = : 0. The correct proof will use 8 of the statements below. Statements to choose from: Note that a₁ = 9a0 + 8. Now assume that P(n) is true for all n ≥ 0. Your Proof: Put chosen statements in order in this column and press the Submit Answers button. Let P(n) be the predicate, "a = 9″ – 1". απ = 90 − 1 = Note that Let P(n) be the predicate, "an 9" - 1 is a solution to the recurrence relation an = 9an-1 +8 with ao = 0." - Now assume that P(k + 1) is true. Thus P(k) is true for all k. Thus P(k+1) is true. Then ak+1 = 9ak +8, so P(k + 1) is true. = 1 − 1 = 0, as required. Then = 9k — 1. ak Now assume that P(k) is true for an arbitrary integer k ≥ 1. By the recurrence relation, we have ak+1 = ak+1 = = 9ak + 8 = 9(9k − 1) + 8 This simplifies to 9k+19+8 = 9k+1 − 1 Then 9k+1 − 1 = 9(9*…

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