Field Strength The field strength H of a magnet of length 2L on a particle r units from the centre of the magnet is H = 2 m L ( r 2 + L 2 ) 3 2 Where ± m are the poles of the magnet. Find the average field strength as the particle moves from 0 to R units from the centre by evaluating the integral. 1 R ∫ 0 R 2 m L ( r 2 + L 2 ) 3 2 d r .
Field Strength The field strength H of a magnet of length 2L on a particle r units from the centre of the magnet is H = 2 m L ( r 2 + L 2 ) 3 2 Where ± m are the poles of the magnet. Find the average field strength as the particle moves from 0 to R units from the centre by evaluating the integral. 1 R ∫ 0 R 2 m L ( r 2 + L 2 ) 3 2 d r .
Solution Summary: The author calculates the average field strength of a magnet of length 2 L as it moves from 0 to R units from the centre.
The field strength H of a magnet of length 2L on a particle r units from the centre of the magnet is
H
=
2
m
L
(
r
2
+
L
2
)
3
2
Where
±
m
are the poles of the magnet. Find the average field strength as the particle moves from 0 to R units from the centre by evaluating the integral.
1
R
∫
0
R
2
m
L
(
r
2
+
L
2
)
3
2
d
r
.
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
I circled the correct, could you explain using stoke
Use Euler's method to numerically integrate
dy
dx
-2x+12x² - 20x +8.5
from x=0 to x=4 with a step size of 0.5. The initial condition at x=0 is y=1. Recall
that the exact solution is given by y = -0.5x+4x³- 10x² + 8.5x+1
Find an equation of the line tangent to the graph of f(x) = (5x-9)(x+4) at (2,6).
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.