As discussed in class, the force on a solid object in Newtons in the direction of a unit vector a as a result of a pressure p(x, y, z) in Pascals, is the negative of the outward surface integral of the vector field pa (x, y, z are in meters). The value of sin (3+4F) where F is the vertical downward force due to the pressure p = k(8.6x² + 6.3y² +3.1z+1), k = 7.84 Newtons/meter 4, on the tetrahedron with vertices (0, 0, 0), (1, 0, 0), (0, 1, 0), (0, 0, 1), is 0.016 -0.069 -0.425 0.544 0.283 0.838 0.346 -0.759

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