solutions 9... solutions solutions... エン (C) 4 (D) 19 2 9 The surface has area 5π (A) ST√5 3 (B) (5√5-1) (C) 2π (D) (5√5-1) 10 If then Σ= {(x2) CR³: == -2+454} y, z) 2 f(t) = e³ H(t - 2) - cos(t)H(t), 4y² t> 0
solutions 9... solutions solutions... エン (C) 4 (D) 19 2 9 The surface has area 5π (A) ST√5 3 (B) (5√5-1) (C) 2π (D) (5√5-1) 10 If then Σ= {(x2) CR³: == -2+454} y, z) 2 f(t) = e³ H(t - 2) - cos(t)H(t), 4y² t> 0
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.2: Graphs Of Equations
Problem 13E
Related questions
Question
100%
Could you show why the answer is B
Using polar coordinates and the area formula

Transcribed Image Text:solutions 9...
solutions
solutions...
エン
(C)
4
(D)
19
2
9 The surface
has area
5π
(A) ST√5
3
(B) (5√5-1)
(C) 2π
(D) (5√5-1)
10 If
then
Σ= {(x2) CR³: == -2+454}
y, z)
2
f(t) = e³ H(t - 2) - cos(t)H(t),
4y²
t> 0
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