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![Find the scalar equation of the plane = [-2,2,7] + s[3, −2,1] + t[−2,1,5]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2ef31c9f-1e44-437f-a71e-09574dc73129%2F1957ce7b-4985-432e-a0b6-9f09749cc4ab%2F4vyy6e_processed.png&w=3840&q=75)
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- Find a scalar equation of the plane that contains the points (−1, −3, 1), (1, 0, 3), and (2, 7, 0).Find an equation of the plane through the three points P =(0,0,4), Q=(-3,4,0), R=(-1,-2,3). You can write your equation in general form or scalar form.Draw v = [ 4/1 ] and w = [ -2/2 ] and v+w and v-w in a single xy plane.
- Find a scalar equation of the plane containing the line x = 4+ 5t, y = 5+ 3t and z = 6+ 4t and the point (-3, –4, – 1).Calculate the triple scalar products w. (v × u) and u ⋅ (w × v), where u = (7, 2, −1), v = w. (vx u) = 330 = (2, 8, -3), and w = u. (w x v) = 350 = (9, 8, -10).Determine the scalar equation of the plane that contains A(-1, 3, 1) and is perpendicular to both 5x - 2y+z-6=0 and 4x + y 2z+ 9 = 0.
