The solution of the initial value problem. = S t y + 4 y √ty 4y = 4 โy(1) = 4 t4 is S У t4 +7 2t4 5t4 - 1 y = t8 1+ ln(t) y = 4 +4 2t21 y = 4 t6 y = 4 + 4 ln(t) For what value of the constant a does the substitution u = ya converts the differential equation 2y' - et y = (ty) ³/2 into a linear first order differential equation in u ? a = -1/2 a = 3/2 a = -3/2 a = = 5/2 О a = -5/2 a = 1/2
The solution of the initial value problem. = S t y + 4 y √ty 4y = 4 โy(1) = 4 t4 is S У t4 +7 2t4 5t4 - 1 y = t8 1+ ln(t) y = 4 +4 2t21 y = 4 t6 y = 4 + 4 ln(t) For what value of the constant a does the substitution u = ya converts the differential equation 2y' - et y = (ty) ³/2 into a linear first order differential equation in u ? a = -1/2 a = 3/2 a = -3/2 a = = 5/2 О a = -5/2 a = 1/2
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 18T
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Transcribed Image Text:The solution of the initial value problem.
=
S t y + 4 y
√ty 4y = 4
โy(1) = 4
t4
is
S
У
t4 +7
2t4
5t4 - 1
y =
t8
1+ ln(t)
y = 4
+4
2t21
y = 4
t6
y = 4 + 4 ln(t)
Transcribed Image Text:For what value of the constant a does the substitution u = ya converts the
differential equation
2y' - et y = (ty) ³/2
into a linear first order differential equation in u ?
a = -1/2
a = 3/2
a = -3/2
a = = 5/2
О
a = -5/2
a = 1/2
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