7. dx -1 x²

Q: 2 1-6 (5x-ex) dx =

A:

Q: 1 dx xV9x² + 4

A:

Q: (x2-4x+8) dx

A:

Q: 1. L= V1 + 16x6 dx

A: First, we factor out 16 from the radical term, So, it becomes,

Q: dx 4. xv9+4x2

A: Method:- I  use Trigonometry substitution method to solve the given integral

Q: (4 dx 2 2X Sxー X-I

A:

Q: dx 35. ex/2 +1

A:

Q: Evaluate dx. /25 – x²

A: First of all, let x = 5 sin (u) and differentiate w.r.t x on both sides of the equation and find dx.

Q: dx x 2+1 3.

A:

Q: I + a dx = 9.

A:

Q: -| Vx³ + 16x² dx

A: Let I=∫x3+16x2 dx I=∫xx+16 dx Let assume x+16=t2⇒dx=2t dt I=∫(t2-16)t(2t) dt =2∫(t4-16t2)dt

Q: v5-x dx

A:

Q: x2 - 4 3 dx

A: The given integral is: I=∫x2-4x3dx

Q: 4-x2 dx -2

A: The given integral is

Q: dx 4x2- 4x+5

A:

Q: 6. 22x+x dx 5. f 22x

A:

Q: 5. (2x + 3V )dx 2х + 3уx

A:

Q: .2 dx 6. (x-1)3

A:

Q: 10. Evaluate (4x-8)ex²-4x+3 dx

A:

Q: Compute 3+r+1 dx x2

A: Given : ∫233x2+2x+1x2dx

Q: dx

A: Our Aim is to integrate the following expression given below:-∫ex(2e2x-4ex-1)dx  -(i)

Q: 1/3y+4=1/5y

A:

Q: Differentiate.

A: ddxxn=n xn-1

Q: 3 + 2х +1 2х +1 2 dx -4

A:

Q: (1-2х)2 dx 3.

A: Given :       ∫1 - 2x2x dx   To evaluate the given integral.

Q: 2. Evaluate. (Зx* - 2х + 1)dx -2

A:

Q: (2x-3)4 dx 10

A: Given:The integral is

Q: ニ dly 2 de

A:

Q: 1 + 2x dx 1

A:

Q: TT/4 3284 ;dx 4+4x2

A:

Q: So 3 -dx 4 9 + 4x CV 9r + 4x³

A: The given definite integral is ∫0329x+4x39+4x4dx