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The solution of the initial value Sty + 2y = โ y(1) = 2 2 y: t2 is 4t2 2 t4 y = 2+2 ln(t) y = - t4 1 6 t² + 1 t2 1+ln(t) y = 2 t2 For what value of the constant a does the substitution u = ya converts the differential equation e³ y' - y = (1/4) 7/2 into a linear first order differential equation in u ? a = : -5/2 a = -1/2 a = 3/2 a = = 1/2 a = 5/2 a = -3/2

The solution of the initial value Sty + 2y = โ y(1) = 2 2 y: t2 is 4t2 2 t4 y = 2+2 ln(t) y = - t4 1 6 t² + 1 t2 1+ln(t) y = 2 t2 For what value of the constant a does the substitution u = ya converts the differential equation e³ y' - y = (1/4) 7/2 into a linear first order differential equation in u ? a = : -5/2 a = -1/2 a = 3/2 a = = 1/2 a = 5/2 a = -3/2

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The solution of the initial value Sty + 2y = โ y(1) = 2 2 y: t2 is 4t2 2 t4 y = 2+2 ln(t) y = - t4 1 6 t² + 1 t2 1+ln(t) y = 2 t2
Transcribed Image Text:The solution of the initial value Sty + 2y = โ y(1) = 2 2 y: t2 is 4t2 2 t4 y = 2+2 ln(t) y = - t4 1 6 t² + 1 t2 1+ln(t) y = 2 t2
For what value of the constant a does the substitution u = ya converts the differential equation e³ y' - y = (1/4) 7/2 into a linear first order differential equation in u ? a = : -5/2 a = -1/2 a = 3/2 a = = 1/2 a = 5/2 a = -3/2
Transcribed Image Text:For what value of the constant a does the substitution u = ya converts the differential equation e³ y' - y = (1/4) 7/2 into a linear first order differential equation in u ? a = : -5/2 a = -1/2 a = 3/2 a = = 1/2 a = 5/2 a = -3/2
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