0.7 Find (arcsin xarcsin y)dydx. It is the volume bounded above by the surface z = arcsin x + arcsiny and the rectangular region depicted in the corner forward facing. z=arcsin(x)+arcsin(y) 1.5 1.01 Z 0.5 0.0 1.0 1.0 0.5 0.5 0.0.0 y

For the sphers x-12+y+22+z-42=36 and x2+y2+z2=64, find the ratio of their a surface areas. b volumes.

A soda can has a volume of 25 cubic inches. Let x denote its radius and h its height, both in inches. a. Using the fact that the volume of the can is 25 cubic inches, express h in terms of x. b. Express the total surface area S of the can in terms of x.

A frustum of a cone is the portion of the cone bounded between the circular base and a plane parallel to the base. With dimensions are indicated, show that the volume of the frustum of the cone is V=13R2H13rh2