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The function f(x) = 5x³ 135x has two critical values x = -3, and x = 3 on the interval [-6,6] A) First critical value, x = -3, is A relative maximum, at value f(-3) = 270 A relative minimum, at value f(-3) = 270 O Neither a relative maximum nor a relative minimum, at value f(-3) = 270 Not enough information to determine B) Second critical value, x = 3, is A relative minimum, at value f(3) = -270 A relative maximum, at value f(3) = -270 Neither a relative maximum nor a relative minimum, at value f(3) = -270 Not enough information to determine C) Find the Absolute Maximum: Absolute Maximum is -3 at x = 270. Absolute Maximum is at more than one x values Absolute Maximum is 270 at x = -3. Not enough information to determin. D) Find the Absolute Minimum: Absolute Minimum is -6 at x = -270. Absolute Minimum is at more than one x values Absolute Minimum is -270 at x = -6. Not enough information to determin.

The function f(x) = 5x³ 135x has two critical values x = -3, and x = 3 on the interval [-6,6] A) First critical value, x = -3, is A relative maximum, at value f(-3) = 270 A relative minimum, at value f(-3) = 270 O Neither a relative maximum nor a relative minimum, at value f(-3) = 270 Not enough information to determine B) Second critical value, x = 3, is A relative minimum, at value f(3) = -270 A relative maximum, at value f(3) = -270 Neither a relative maximum nor a relative minimum, at value f(3) = -270 Not enough information to determine C) Find the Absolute Maximum: Absolute Maximum is -3 at x = 270. Absolute Maximum is at more than one x values Absolute Maximum is 270 at x = -3. Not enough information to determin. D) Find the Absolute Minimum: Absolute Minimum is -6 at x = -270. Absolute Minimum is at more than one x values Absolute Minimum is -270 at x = -6. Not enough information to determin.

College Algebra (MindTap Course List)
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter4: Polynomial And Rational Functions
Section4.2: Polynomial Functions
Problem 96E: What is the purpose of the Intermediate Value Theorem?
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The function f(x) = 5x³ 135x has two critical values x = -3, and x = 3 on the interval [-6,6] A) First critical value, x = -3, is A relative maximum, at value f(-3) = 270 A relative minimum, at value f(-3) = 270 O Neither a relative maximum nor a relative minimum, at value f(-3) = 270 Not enough information to determine B) Second critical value, x = 3, is A relative minimum, at value f(3) = -270 A relative maximum, at value f(3) = -270 Neither a relative maximum nor a relative minimum, at value f(3) = -270 Not enough information to determine
Transcribed Image Text:The function f(x) = 5x³ 135x has two critical values x = -3, and x = 3 on the interval [-6,6] A) First critical value, x = -3, is A relative maximum, at value f(-3) = 270 A relative minimum, at value f(-3) = 270 O Neither a relative maximum nor a relative minimum, at value f(-3) = 270 Not enough information to determine B) Second critical value, x = 3, is A relative minimum, at value f(3) = -270 A relative maximum, at value f(3) = -270 Neither a relative maximum nor a relative minimum, at value f(3) = -270 Not enough information to determine
C) Find the Absolute Maximum: Absolute Maximum is -3 at x = 270. Absolute Maximum is at more than one x values Absolute Maximum is 270 at x = -3. Not enough information to determin. D) Find the Absolute Minimum: Absolute Minimum is -6 at x = -270. Absolute Minimum is at more than one x values Absolute Minimum is -270 at x = -6. Not enough information to determin.
Transcribed Image Text:C) Find the Absolute Maximum: Absolute Maximum is -3 at x = 270. Absolute Maximum is at more than one x values Absolute Maximum is 270 at x = -3. Not enough information to determin. D) Find the Absolute Minimum: Absolute Minimum is -6 at x = -270. Absolute Minimum is at more than one x values Absolute Minimum is -270 at x = -6. Not enough information to determin.
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