Start with a circle of radius r=9. Form the two shaded regions pictured below. Let f(6) be the area of the shaded region on the left which has an arc and two straight line sides. Let g(6) be the area of the shaded region on the right which is a right triangle. Note that the areas of these two regions will be functions of 6; r=9 is fixed in the problem. 0 f(0) (a) Find a formula for f(6)= | | (b)Find a formula for g(6)= lim ƒ (6) (c) 80 = lim g (0) (d) 80 = lim (e) [f(8)/g(6)]= 0 g(0)

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
Chapter3: Straight Lines And Linear Functions
Section3.FR3: A Further Look: Secant Lines
Problem 1TU
Question
Start with a circle of radius r=9. Form the two shaded regions pictured below.
Let f(6) be the area of the shaded region on the left which has an arc and two straight line sides.
Let g(6) be the area of the shaded region on the right which is a right triangle. Note that the areas of these two regions will be functions of 6; r=9 is fixed in the problem.
0
f(0)
(a) Find a formula for f(6)= | |
(b)Find a formula for g(6)=
lim ƒ (6)
(c) 80
=
lim g (0)
(d) 80
=
lim
(e) [f(8)/g(6)]=
0
g(0)
Transcribed Image Text:Start with a circle of radius r=9. Form the two shaded regions pictured below. Let f(6) be the area of the shaded region on the left which has an arc and two straight line sides. Let g(6) be the area of the shaded region on the right which is a right triangle. Note that the areas of these two regions will be functions of 6; r=9 is fixed in the problem. 0 f(0) (a) Find a formula for f(6)= | | (b)Find a formula for g(6)= lim ƒ (6) (c) 80 = lim g (0) (d) 80 = lim (e) [f(8)/g(6)]= 0 g(0)
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