Explanation Given information: The given numbers are A = 330 and B = 156 . Calculation: Take 0 th iteration, the values are a = A , b = B , s = 1 , t = 0 , u = 0 , v = 1 . Note that, s a + t b = 1 ⋅ 330 + 0 ⋅ 156 = 330 . Iteration 0 a 330 b 156 r q s 1 t 0 u 0 v 1 new u new v s a + t b 330 Take 1 th iteration of the while-loop. r = a mod b = 330 mod 156 = 18 q = a div b = 330 div 156 = 2 a = b = 156 b = r = 18 n e w u = s − u q = 1 − 0 ⋅ 2 = 1 n e w v = t − v q = 0 − 1 ⋅ 2 = − 2 s = u = 0 t = v = 1 u = n e w u = 1 v = n e w v = − 2 s a + t b = 0 ⋅ 156 + 1 ⋅ 18 = 18 Iteration 0 1 a 330 156 b 156 18 r 18 q 2 s 1 0 t 0 1 u 0 1 v 1 − 2 new u 1 new v − 2 s a + t b 330 18 Take 2 th iteration of the while-loop. r = a mod b = 156 mod 18 = 12 q = a div b = 156 div 18 = 8 a = b = 18 b = r = 12 n e w u = s − u q = 0 − 1 ⋅ 8 = − 8 n e w v = t − v q = 1 − ( − 2 ) ⋅ 8 = 1 + 16 = 17 s = u = 1 t = v = − 2 u = n e w u = − 8 v = n e w v = 17 s a + t b = 1 ⋅ 18 + ( − 2 ) ⋅ 12 = − 6 Iteration 0 1 2 a 330 156 18 b 156 18 12 r 18 12 q 2 8 s 1 0 1 t 0 1 − 2 u 0 1 − 8 v 1 − 2 17 new u 1 − 8 new v − 2 17 s a + t b 330 18 − 6 Take 3 th iteration of the while-loop

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Chapter 8.4, Problem 28ES

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A table with values s,t and sA+tB before the while loop and after the loop.

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Chapter 8.4, Problem 27ES

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A table with values s , t and s A + t B before the while loop and after the loop.

Solution Summary: The author calculates a table with values s,tandsA+tB before the while loop and after the loop.

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To calculate:

A table with values s,t and sA+tB before the while loop and after the loop.

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Chapter 8 Solutions

A table with values s , t and s A + t B before the while loop and after the loop.

Solution Summary: The author calculates a table with values s,tandsA+tB before the while loop and after the loop.

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To calculate: A table with values s,t and sA+tB before the while loop and after the loop.

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Chapter 8 Solutions

To calculate:

A table with values s,t and sA+tB before the while loop and after the loop.