ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM
ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM
7th Edition
ISBN: 9781319403959
Author: ATKINS
Publisher: MAC HIGHER
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 8, Problem 8A.1AST
Interpretation Introduction

Interpretation:

The element that has the greatest polarizability has to be given.

Concept Introduction:

Polarizability is the measure with which an electron cloud can be distorted by charges on neighboring species and is greatest for the electron-rich, heavier atoms of a group.

Polarizability of atoms tends to decreases from left to right across a period and increases down a group.

Expert Solution & Answer
Check Mark

Answer to Problem 8A.1AST

Germanium has the greatest polarizability.

Explanation of Solution

Polarizability of atoms tends to decreases from left to right across a period and increases down a group.

Carbon and germanium belongs to group 14, aluminium belongs to group 13.

The number of electrons in carbon is six.

The number of electrons in aluminum is twelve.

The number of electrons in germanium is thirty-two.

The greater the numbers of electrons, the less control the nuclear charge on distribution of charges, and thus the increased polarizability of the atom.

Therefore, Germanium will have the greatest polarizability compared to carbon and aluminum.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Instructions: Complete the questions in the space provided. Show all your work 1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure the initial reaction rate and the starting concentrations of the reactions for 4 trials. BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l) Initial rate Trial [BrO3] [H*] [Br] (mol/L) (mol/L) | (mol/L) (mol/L.s) 1 0.10 0.10 0.10 8.0 2 0.20 0.10 0.10 16 3 0.10 0.20 0.10 16 4 0.10 0.10 0.20 32 a. Based on the above data what is the rate law expression? b. Solve for the value of k (make sure to include proper units) 2. The proposed reaction mechanism is as follows: i. ii. BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq) HBrO³ (aq) + H* (aq) → H₂BrO3* (aq) iii. H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l) [Fast] [Medium] [Slow] iv. Br₂O₂ (aq) + 4H*(aq) + 4Br‍(aq) → 3Br₂ (l) + H2O (l) [Fast] Evaluate the validity of this proposed reaction. Justify your answer.
е. Д CH3 D*, D20
C. NaOMe, Br Br

Chapter 8 Solutions

ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM

Ch. 8 - Prob. 8A.7ECh. 8 - Prob. 8A.8ECh. 8 - Prob. 8A.9ECh. 8 - Prob. 8A.10ECh. 8 - Prob. 8A.11ECh. 8 - Prob. 8A.12ECh. 8 - Prob. 8A.13ECh. 8 - Prob. 8A.14ECh. 8 - Prob. 8A.15ECh. 8 - Prob. 8A.16ECh. 8 - Prob. 8A.17ECh. 8 - Prob. 8A.18ECh. 8 - Prob. 8A.19ECh. 8 - Prob. 8A.20ECh. 8 - Prob. 8B.1ASTCh. 8 - Prob. 8B.1BSTCh. 8 - Prob. 8B.2ASTCh. 8 - Prob. 8B.2BSTCh. 8 - Prob. 8B.1ECh. 8 - Prob. 8B.2ECh. 8 - Prob. 8B.3ECh. 8 - Prob. 8B.4ECh. 8 - Prob. 8B.5ECh. 8 - Prob. 8B.6ECh. 8 - Prob. 8B.7ECh. 8 - Prob. 8B.8ECh. 8 - Prob. 8C.1ASTCh. 8 - Prob. 8C.1BSTCh. 8 - Prob. 8C.2BSTCh. 8 - Prob. 8C.1ECh. 8 - Prob. 8C.2ECh. 8 - Prob. 8C.3ECh. 8 - Prob. 8C.4ECh. 8 - Prob. 8C.5ECh. 8 - Prob. 8C.6ECh. 8 - Prob. 8D.1ASTCh. 8 - Prob. 8D.1BSTCh. 8 - Prob. 8D.2ASTCh. 8 - Prob. 8D.2BSTCh. 8 - Prob. 8D.1ECh. 8 - Prob. 8D.2ECh. 8 - Prob. 8D.3ECh. 8 - Prob. 8D.4ECh. 8 - Prob. 8D.5ECh. 8 - Prob. 8D.6ECh. 8 - Prob. 8D.7ECh. 8 - Prob. 8D.8ECh. 8 - Prob. 8E.1ASTCh. 8 - Prob. 8E.1BSTCh. 8 - Prob. 8E.2ASTCh. 8 - Prob. 8E.2BSTCh. 8 - Prob. 8E.1ECh. 8 - Prob. 8E.2ECh. 8 - Prob. 8E.3ECh. 8 - Prob. 8E.4ECh. 8 - Prob. 8E.5ECh. 8 - Prob. 8E.6ECh. 8 - Prob. 8E.7ECh. 8 - Prob. 8E.8ECh. 8 - Prob. 8F.1ASTCh. 8 - Prob. 8F.1BSTCh. 8 - Prob. 8F.2ASTCh. 8 - Prob. 8F.2BSTCh. 8 - Prob. 8F.1ECh. 8 - Prob. 8F.2ECh. 8 - Prob. 8F.3ECh. 8 - Prob. 8F.4ECh. 8 - Prob. 8F.5ECh. 8 - Prob. 8F.6ECh. 8 - Prob. 8G.1ASTCh. 8 - Prob. 8G.1BSTCh. 8 - Prob. 8G.2ASTCh. 8 - Prob. 8G.2BSTCh. 8 - Prob. 8G.1ECh. 8 - Prob. 8G.2ECh. 8 - Prob. 8G.3ECh. 8 - Prob. 8G.4ECh. 8 - Prob. 8G.5ECh. 8 - Prob. 8G.6ECh. 8 - Prob. 8G.7ECh. 8 - Prob. 8G.8ECh. 8 - Prob. 8G.9ECh. 8 - Prob. 8G.10ECh. 8 - Prob. 8H.1ASTCh. 8 - Prob. 8H.1BSTCh. 8 - Prob. 8H.2ASTCh. 8 - Prob. 8H.2BSTCh. 8 - Prob. 8H.1ECh. 8 - Prob. 8H.2ECh. 8 - Prob. 8H.3ECh. 8 - Prob. 8H.4ECh. 8 - Prob. 8H.5ECh. 8 - Prob. 8H.6ECh. 8 - Prob. 8H.7ECh. 8 - Prob. 8H.8ECh. 8 - Prob. 8H.10ECh. 8 - Prob. 8H.11ECh. 8 - Prob. 8H.12ECh. 8 - Prob. 8I.1ASTCh. 8 - Prob. 8I.1BSTCh. 8 - Prob. 8I.2ASTCh. 8 - Prob. 8I.2BSTCh. 8 - Prob. 8I.1ECh. 8 - Prob. 8I.2ECh. 8 - Prob. 8I.3ECh. 8 - Prob. 8I.5ECh. 8 - Prob. 8I.6ECh. 8 - Prob. 8I.7ECh. 8 - Prob. 8I.8ECh. 8 - Prob. 8I.9ECh. 8 - Prob. 8I.10ECh. 8 - Prob. 8I.11ECh. 8 - Prob. 8I.12ECh. 8 - Prob. 8I.13ECh. 8 - Prob. 8I.14ECh. 8 - Prob. 8I.15ECh. 8 - Prob. 8I.16ECh. 8 - Prob. 8J.1ASTCh. 8 - Prob. 8J.1BSTCh. 8 - Prob. 8J.1ECh. 8 - Prob. 8J.2ECh. 8 - Prob. 8J.3ECh. 8 - Prob. 8J.4ECh. 8 - Prob. 8J.5ECh. 8 - Prob. 8J.6ECh. 8 - Prob. 8J.7ECh. 8 - Prob. 8J.8ECh. 8 - Prob. 8.3ECh. 8 - Prob. 8.4ECh. 8 - Prob. 8.5ECh. 8 - Prob. 8.6ECh. 8 - Prob. 8.7ECh. 8 - Prob. 8.8ECh. 8 - Prob. 8.9ECh. 8 - Prob. 8.11ECh. 8 - Prob. 8.12ECh. 8 - Prob. 8.13ECh. 8 - Prob. 8.14ECh. 8 - Prob. 8.15ECh. 8 - Prob. 8.17ECh. 8 - Prob. 8.18ECh. 8 - Prob. 8.19ECh. 8 - Prob. 8.20ECh. 8 - Prob. 8.21ECh. 8 - Prob. 8.22ECh. 8 - Prob. 8.25ECh. 8 - Prob. 8.29ECh. 8 - Prob. 8.31CE
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Text book image
General Chemistry - Standalone book (MindTap Cour...
Chemistry
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Cengage Learning
Text book image
Living By Chemistry: First Edition Textbook
Chemistry
ISBN:9781559539418
Author:Angelica Stacy
Publisher:MAC HIGHER
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry: An Atoms First Approach
Chemistry
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781133611097
Author:Steven S. Zumdahl
Publisher:Cengage Learning
Quantum Mechanics - Part 1: Crash Course Physics #43; Author: CrashCourse;https://www.youtube.com/watch?v=7kb1VT0J3DE;License: Standard YouTube License, CC-BY