The key distinction and the factors for the distinction between sublevel energies in one electron species, such as the H atom and those in many-electron species, such as the C atom is to be determined. Also whether the pattern of sublevel energies in Be 3 + is more like that in H or C atom is to be explained. Concept introduction: The species that contain a single nucleus with a single electron is called one-electron species. Hydrogen is the only atom in the periodic table that has a single electron in the orbitals in the ground state. The species with more than one electron is known as the multi-electron system. Examples of many-electron systems are helium and nitrogen.

Question

Want to see the full answer?

Answer 1

Question

Chapter 8, Problem 8.8P

Interpretation Introduction

Interpretation:

The key distinction and the factors for the distinction between sublevel energies in one electron species, such as the H atom and those in many-electron species, such as the C atom is to be determined. Also whether the pattern of sublevel energies in Be3+ is more like that in H or C atom is to be explained.

Concept introduction:

The species that contain a single nucleus with a single electron is called one-electron species. Hydrogen is the only atom in the periodic table that has a single electron in the orbitals in the ground state.

The species with more than one electron is known as the multi-electron system. Examples of many-electron systems are helium and nitrogen.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

None

3. Consider the compounds below and determine if they are aromatic, antiaromatic, or non-aromatic. In case of aromatic or anti-aromatic, please indicate number of I electrons in the respective systems. (Hint: 1. Not all lone pair electrons were explicitly drawn and you should be able to tell that the bonding electrons and lone pair electrons should reside in which hybridized atomic orbital 2. You should consider ring strain- flexibility and steric repulsion that facilitates adoption of aromaticity or avoidance of anti- aromaticity) H H N N: NH2 N Aromaticity (Circle) Aromatic Aromatic Aromatic Aromatic Aromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic aromatic TT electrons Me H Me Aromaticity (Circle) Aromatic Aromatic Aromatic Aromatic Aromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic aromatic πT electrons H HH…

A chemistry graduate student is studying the rate of this reaction: 2 HI (g) →H2(g) +12(g) She fills a reaction vessel with HI and measures its concentration as the reaction proceeds: time (minutes) [IH] 0 0.800M 1.0 0.301 M 2.0 0.185 M 3.0 0.134M 4.0 0.105 M Use this data to answer the following questions. Write the rate law for this reaction. rate = 0 Calculate the value of the rate constant k. k = Round your answer to 2 significant digits. Also be sure your answer has the correct unit symbol.