Chapter 8, Problem 8.44NP

Interpretation Introduction

Interpretation:

The vapor pressure of the krypton is shown as:

  ${\text{log}}_{\text{10}}\left(\frac{\text{P}}{\text{torr}}\right)\text{=}\text{b}\text{-}\text{0}\text{.05223}\left(\frac{\text{a}}{\text{T/K}}\right)$

The triple point temperature and pressure should be predicted. Also, the enthalpies of vaporization, fusion and sublimation of the krypton should be predicted.

Concept Introduction:

The point at which liquid, solid and vapor exists at equilibrium is known as the triple point. When heat is required to change the 1 mole of a substance from solid to gas at a standard temperature and pressure is known as enthalpy of sublimation.

When heat is required to change the 1 mole of a substance from liquid to gas at a standard temperature and pressure is known as enthalpy of vaporization.

When heat is required to change the 1 mole of a substance from solid to liquid at a standard temperature and pressure is known as enthalpy of vaporization.